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Find child element

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Lachlan
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Lachlan asked on 09 Oct 2012, 06:02 AM
Hi,

This is a somewhat convoluted request, but I'll do my best to describe it!

I am trying to test a section of our app, and we are using the Rad Treeview control which has been slightly modified to incorporate some extra functionality. From what I can see, on the front end the treeview is built using a series of divs and spans, most of which use the same classes. I am trying to find particular nodes in the treeview but our modifications pass id's (which are randomly generated) to the particular nodes, so I cannot use these for finding elements.

A sample of code containing the elements I am trying to find is below. In particular I am trying to find the span with the id thisSpan_randomId. All of the specific attributes of this element are shared with other objects in the DOM.

<div class="rtBot">   
    <span class="rtSp"></span>  
    <span class="rtPlus"></span>  
    <img src="" longdesc="Region" alt="" class="rtImg">  
    <span class="rtIn">TS Test Region  
       <span class="tvContext" name="contextMenu" style="display:none;" id="thisSpan_randomId">  
          <a href='javascript:addRegionAccess("","747383be52bd4960b0b12331ed690c26", "TS%20Test%20Region");' innerhtml="Add Region Access" class="addRegion">Add Region Access</a>  
       </span>  
    </span>  
</div>

Using the Find Element dialog, I can locate the parent of the element I am trying to find using TextContent is exactly TS Test Region, but the child has no particular identifiers that I can use that are not already shared with other elements on the page.

Is there a way I can find this child element (with no unique identifiers) by first finding the parent (with unique identifiers)?

Hopefully this makes a bit of sense!

Cheers,

Lachlan

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Byron
Telerik team
answered on 11 Oct 2012, 10:21 PM
Hello Lachlan,

I just published a new user guide article to describe a solution to this problem: chained find expressions. Please let me know if this helps resolve your issue.

Kind regards,
Byron
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Lachlan
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answered on 11 Oct 2012, 10:28 PM
That's perfect Byron, works like a charm!

Thanks!
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