This is a migrated thread and some comments may be shown as answers.

XMLHttpRequest.open

0 Answers 63 Views
Ajax
This is a migrated thread and some comments may be shown as answers.
Martin
Top achievements
Rank 1
Martin asked on 03 Oct 2014, 08:47 AM
I am trying to follow the ajax tutorial at wschools.com. However when I copy and paste this code it does not work:

<!DOCTYPE html>
<html>
<head>
<script>
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","ajax_info.txt",true);
xmlhttp.send();
}
</script>
</head>
<body>

<div id="myDiv"><h2>Let AJAX change this text</h2></div>
<button type="button" onclick="loadXMLDoc()">Change Content</button>

</body>
</html>





No answers yet. Maybe you can help?

Tags
Ajax
Asked by
Martin
Top achievements
Rank 1
Share this question
or