3 Answers, 1 is accepted
0
Accepted
Hello Patxi,
Here's a sample code snippet that shows the needed appraoch.
Regards,
Paul
the Telerik team
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Here's a sample code snippet that shows the needed appraoch.
<form id="form1" runat="server"> |
<telerik:RadScriptManager ID="RadScriptManager1" runat="server"> |
</telerik:RadScriptManager> |
<script type="text/javascript"> |
function OnClientNodeClicked(sender, eventArgs) { |
var node = eventArgs.get_node(); |
if (node.get_level() != 0) { |
var parentNode = node.get_parent(); |
alert(parentNode.get_value()); |
} |
} |
</script> |
<telerik:RadTreeView ID="RadTreeView1" runat="server" OnClientNodeClicked="OnClientNodeClicked"> |
<Nodes> |
<telerik:RadTreeNode runat="server" Text="Root RadTreeNode1" Value="root1"> |
<Nodes> |
<telerik:RadTreeNode runat="server" Text="Child RadTreeNode 1"> |
</telerik:RadTreeNode> |
<telerik:RadTreeNode runat="server" Text="Child RadTreeNode 2"> |
</telerik:RadTreeNode> |
</Nodes> |
</telerik:RadTreeNode> |
<telerik:RadTreeNode runat="server" Text="Root RadTreeNode2" Value="root2"> |
<Nodes> |
<telerik:RadTreeNode runat="server" Text="Child RadTreeNode 1"> |
</telerik:RadTreeNode> |
<telerik:RadTreeNode runat="server" Text="Child RadTreeNode 2"> |
</telerik:RadTreeNode> |
<telerik:RadTreeNode runat="server" Text="Child RadTreeNode 3"> |
</telerik:RadTreeNode> |
</Nodes> |
</telerik:RadTreeNode> |
</Nodes> |
</telerik:RadTreeView> |
</form> |
Regards,
Paul
the Telerik team
Instantly find answers to your questions on the new Telerik Support Portal.
Check out the tips for optimizing your support resource searches.
0
Accepted
Princy
Top achievements
Rank 2
answered on 21 Apr 2009, 11:07 AM
Hello Patxi,
The server side equivalent for the above code is as follows:
c#:
Thanks
Princy.
The server side equivalent for the above code is as follows:
c#:
protected void RadTreeView1_NodeClick(object sender, RadTreeNodeEventArgs e) |
{ |
RadTreeNode myParentNode = e.Node.ParentNode; |
if (myParentNode != null) |
{ |
string mynode = myParentNode.Text; |
} |
} |
Thanks
Princy.
0
Patxi
Top achievements
Rank 1
answered on 21 Apr 2009, 11:25 AM
Thanks Paul and Princy!
fast answer and better solution :)
Both are all right.
fast answer and better solution :)
Both are all right.