Is there a way to get the file name under temporary folder after uploading?

[Jin]

I upload a document and click a button, I want to get the file name under temporary folder for the uploaded document.How can I get it?

[Jin]

Any solution?

[Kate]

Hi Jin,

I believe that the following help article would be very useful in your scenario - Adding Information to Uploaded Files. Using the described approach you can add any additional information for the uploaded files that you need.

Kind regards,
Kate
the Telerik team

[Jin]

Hi Kate,

Maybe you don't understand my meaning. For example, if you upload a document whose name "ad.docx", then after uploaded, the file name under templorary folder is 1347362267483ad.docx. My question is that how to get the file name "1347362267483ad.docx"?

[Plamen]

Hi,

Basically the files in the Temporary Folder are supposed to be used only by the internal functionality of RadAsyncUpload and we do not recommended using them. Here is one way to get the file names of the already uploaded files in the target folder:

protected void RadAsyncUpload1_FileUploaded(object sender, FileUploadedEventArgs e)
   {
       string targetFolder = Server.MapPath(RadAsyncUpload1.TargetFolder);
       string fileName = e.File.GetName();

       Response.Write("@" + targetFolder + fileName);
   }

Hope this will be helpful.

Regards,
Plamen
the Telerik team

[Susheel]

Hi

 i have the same issue and i am wondring.
i am uploading one image named test.jpg but it gets saved in temp folder as  1420013322271test.jpg but at client side i am getting name as test.jpg but i need the file name from temp folder because i want to save that image in database in Base64 format for that i need file with full path for that i am trying to read file from temp folder.

please help me to do my task.

or if any one can tell me that what exacelly added before the file name.

[Plamen]

Hi,

In case you want to save the file in database we recommend using custom handler as for example it is done in this online demo.

Hope this will help you solve the issue.

Regards,
Plamen
Telerik

 

 

[Johann]

Hi, 

Try This.

foreach(UploadedFile file in rauUploadFiles.UploadedFiles)
 {
     FileStream tmpFile = (FileStream) file.InputStream;
List<String> currentImages = Directory.GetFiles(HttpContext.Current.Server.MapPath("~/temp")).Where(f => f.Equals(tmpFile.Name)).ToList();

 }

[Richard Irwin]

In my case I just need to get to the file to open the stream (I don't need to put it in a database) how do I get the temporary file name on the client side?

[Plamen]

Hello,

In general the temporary file name is only for internal and it is not available on the client. In your case you can use custom handler and implement your custom logic there. 

Regards,
Plamen
Telerik