All Day Appointment

[Stuart Hemming]

In this forum thread we're told that an appointment is 'All day' if the appointment starts at 12AM one day and ends at 12AM the next.

If I go to the Scheduler First Look demo and add an appointment in the all day section, the appointment is created with its start and end at 12AM on the SAME day. But if I edit one of the existing all day appointments, it is set up to start and end at 12AM on consecutive days.

What's right?

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Stuart

[Stuart Hemming]

Anyone?

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Stuart

[Nikolay Tsenkov]

Hello Stuart,

Your observation is correct and we will will log this as a bug in the advanced form.
Once the bug is fixed we will let you know.

Thank you for reporting this to our team!
Your telerik points are updated.


Regards,
Nikolay Tsenkov
the Telerik team

[Stuart Hemming]

Nikolay

Can you tell me what is the correct way for this to operate?

Is it supposed to be from 00:00 on one day to 00:00 on the next?

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Stuart

[Nikolay Tsenkov]

Hi Stuart Hemming,

"Is it supposed to be from 00:00 on one day to 00:00 on the next?"
 - On lower level the allDay appointment is persisted holding only the dates (no specific time). And having a choice we try to present the time in the most expected way, which currently seems to be day(x) to day(x + (n - 1)) where n is the duration in days, when the allDay checkbox is checked and 12 am day(x) to 12 am day(x + n) when it's not checked.
E.g. appointment having 1 day duration starting 12/24/2010 will be presented:
 - 12/24/2010 - 12/24/2010 when AllDay is checked;
 -  12am 12/24/2010 - 12am 12/25/2010 otherwise.

We decided this is the best approach since by the checkbox, the user already has the information that this appointment has a multiple of 1-day duration, so he shouldn't be guessing if, either, the start or the end date is included in this period (they are included).

The bug that I thought you reported was that after you uncheck the checkbox the selected time period becomes false - instead selecting the timeFrame between 12 am day(x) to 12 am day(x + n) the format is 12 am day(x) to 12 am day(x + (n - 1)).

I hope this makes it clear.


Regards,
Nikolay Tsenkov
the Telerik team

[Stuart Hemming]

> I hope this makes it clear.
Thanks you. Yes.

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Stuart