[Solved] One dataSource to rule them all.

[Phil H.]

Hi:

I was looking for a way to have one dataSource for a table but have multiple views.  View could be a grid, listView and details view.  But to have paging in the grid I would need to extend the base dataSource.  I am currently, I am doing that with my models using the define.  I am looking for a similar thing for dataSources but having variations for paging, etc.

Phil  

[Petur Subev]

Hello Phil,

Using a shared dataSource might create behaviors that you are not looking for - for example if you have ListView and Grid bound to the same DataSource instance object then paging the Grid will make the ListView page as well.

http://demos.telerik.com/kendo-ui/datasource/shared-datasource

If you want to have the configuration at one place it is possible, but you should have different instances of the dataSource (when object literal is passed to the dataSource the widget creates the dataSource internally).

e.g.

var dsConfig = {
       transport: {
               read: {
                       url: "someUrl"
               }
       },
       schema: {
             model: ...
       }
}

$("#listView").kendoListView({
          dataSource: dsConfig
          //... other options
})

$("#grid").kendoListView({
          dataSource: dsConfig
          //... other options
})

Regards,
Petur Subev
Telerik

 

 

[Phil H.]

Hi All:

I am currently placing table specific in it's own table container as follows (data source is generic):

TableCont = {
  ...
}
TableCont.ProdModel = kendo.data.Model.define({
  ...
});
TableCont.prodDataSource = new kendo.data.DataSource({
  ...
});

Then in specific implementation, I am doing the following:

TableCont.prodDataSource.pageSize(5);

$('#grid').kendoGrid({
  dataSource: TableCont.prodDataSource,
  ...
});

Phil