Zeus_developer
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Rank 1
Zeus_developer
asked on 18 May 2012, 09:22 PM
Hi,
I'm trying the ASP.NET AJAX suite, and I don't know how to solve this function:
I have two treeviews:
I try to implement the functionality: processes(first preeview) and activities(second treeview), where a process can have multiple activities, but a activity can't have processes as child.
I hope you can help me.
Regards
I'm trying the ASP.NET AJAX suite, and I don't know how to solve this function:
I have two treeviews:
- First treeview will receive nodes from second treeview
- node from one treeview can't be moved to nodes of the same treeview
- nodes of second treeview can be moved only to first treeview
- nodes of first treeview can't be moved to second treeview
I try to implement the functionality: processes(first preeview) and activities(second treeview), where a process can have multiple activities, but a activity can't have processes as child.
I hope you can help me.
Regards
5 Answers, 1 is accepted
0
Zeus_developer
Top achievements
Rank 1
answered on 19 May 2012, 04:23 PM
no idea?
0
Accepted

Princy
Top achievements
Rank 2
answered on 21 May 2012, 07:46 AM
Hi,
Here is the sample code which I tried based on your scenario.
ASPX:
C#:
Hope this helps.
Thanks,
Princy.
Here is the sample code which I tried based on your scenario.
ASPX:
<
telerik:RadTreeView
ID
=
"RadTreeView1"
runat
=
"server"
EnableDragAndDrop
=
"true"
EnableDragAndDropBetweenNodes
=
"false"
>
.............
</
telerik:RadTreeView
>
<
telerik:RadTreeView
ID
=
"RadTreeView2"
runat
=
"server"
EnableDragAndDrop
=
"true"
EnableDragAndDropBetweenNodes
=
"false"
onnodedrop
=
"RadTreeView2_NodeDrop"
>
..............
</
telerik:RadTreeView
>
C#:
protected
void
RadTreeView2_NodeDrop(
object
sender, Telerik.Web.UI.RadTreeNodeDragDropEventArgs e)
{
RadTreeNode sourceNode = e.SourceDragNode;
RadTreeNode destNode = e.DestDragNode;
RadTreeViewDropPosition dropPosition = e.DropPosition;
if
((sourceNode.TreeView.Equals(destNode.TreeView)) || ((sourceNode.TreeView == RadTreeView2) && (destNode.TreeView != RadTreeView1)))
{
return
;
}
else
{
destNode.Nodes.Add(sourceNode);
}
}
Hope this helps.
Thanks,
Princy.
0
Zeus_developer
Top achievements
Rank 1
answered on 21 May 2012, 09:18 PM
Princy,
Thanks for your response, it solves part of the problem.
I'm attaching two images where I describe two cases to validate
please take a look at the images and help me to get a solution.
Best regards.
Thanks for your response, it solves part of the problem.
I'm attaching two images where I describe two cases to validate
please take a look at the images and help me to get a solution.
Best regards.
0
Accepted

Princy
Top achievements
Rank 2
answered on 22 May 2012, 05:28 AM
Hi,
Based on your scenario I have modified the code as follows.
C#:
Hope this helps.
Thanks,
Princy.
Based on your scenario I have modified the code as follows.
C#:
protected
void
RadTreeView2_NodeDrop(
object
sender, Telerik.Web.UI.RadTreeNodeDragDropEventArgs e)
{
RadTreeNode sourceNode = e.SourceDragNode;
RadTreeNode destNode = e.DestDragNode;
RadTreeViewDropPosition dropPosition = e.DropPosition;
if
((sourceNode.TreeView.Equals(destNode.TreeView)) || ((sourceNode.TreeView == RadTreeView2) && (destNode.TreeView != RadTreeView1)) || (destNode.Level != 0))
{
return
;
}
else
{
destNode.Nodes.Add(sourceNode);
}
}
Hope this helps.
Thanks,
Princy.
0
Zeus_developer
Top achievements
Rank 1
answered on 22 May 2012, 03:49 PM
Thanks Princy,
that's the solution, you did it again!!
Best regards.
that's the solution, you did it again!!
Best regards.