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Error:While clicking on radcombox

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ComboBox

This is a migrated thread and some comments may be shown as answers.

Ram asked on 08 Nov 2011, 01:31 PM

Hi,

I am getting following javascript error while clicking on combo box

'top' is null or not an object
but with up and down arrows i am able to change the items in combo box
I am declared combo as follows:and this combo is in popup window

<telerik:RadComboBox ID="rad1" runat="server">

<Items>

telerik:RadComboBoxItem Text="1" Value="1" />

<telerik:RadComboBoxItem Text="2" Value="2" />

<telerik:RadComboBoxItem Text="3" Value="3" />

<telerik:RadComboBoxItem Text="4" Value="4" />

<telerik:RadComboBoxItem Text="5" Value="5" />

<telerik:RadComboBoxItem Text="6" Value="6" />

<telerik:RadComboBoxItem Text="7" Value="7" />

<telerik:RadComboBoxItem Text="8" Value="8" />

<telerik:RadComboBoxItem Text="9" Value="9" />

</Items>

</telerik:RadComboBox>

can any one help in solving the issue?

Thanks,

4 Answers, 1 is accepted

answered on 25 Feb 2014, 08:34 PM

Hi Kate,

Any update on this? I have exact same issue as Ram has.
We just update ASP.NET AJAX to 2013.3.1324.40 the latest version. But when click the combobox on IE8, the Jscript run time error is thrown:

Microsoft JScript runtime error: 'top' is null or not an object

if(this._getHeaderElement()){c+=this._getHeaderElement().offsetHeight;
}if(this._getFooterElement()){c+=this._getFooterElement().offsetHeight;
}if(this.get_moreResultsBoxElement()){c+=this.get_moreResultsBoxElement().offsetHeight;
}return c;
};
b.RadComboBox.prototype._calculateItemsHeight=function(){var d=0;
var e=this.get_items().get_count();
for(var c=0;
c<e;
c++){d+=this.get_items().getItem(c).get_element().offsetHeight;
}return d;
};
b.RadComboBox.prototype._getOffsetParentOffset=function(c){var h=0;
var f=0;
var d=a(c.offsetParent);
if(d.css("position")!="static"){var g=d.offset();
h=g.top; <<<<<<<<<---------------------------------------------------------------------------------------------------------------------------

Hope to hear from you soon. Thanks.

Wesley Fang