Drag to Grid and get position

[Jon]

I have a treeview that the user can drag items from and drop them on a grid.  Currently the dropped items go to the bottom of the grid.  Is there a way I can get the row that the user dropped the items on?

The method that handles the drop is :

protected void tvReportColumn_HandleDrop(object sender, RadTreeNodeDragDropEventArgs e)
{
    RadTreeNode sourceNode = e.SourceDragNode;
    RadTreeNode destNode = e.DestDragNode;
    if ((e.HtmlElementID == RadGrid1.ClientID))
    {
        foreach (RadTreeNode node in e.DraggedNodes)
        {
            AddRowToGrid(node);
        }
    }

    RadGrid1.Rebind();
}

[Marin]

Hello Jon,

You can perform this check on the client in the OnClientNodeDropping event like that:

var cell = args.get_htmlElement();
                    if (cell instanceof HTMLTableDataCellElement)
                    {
                        var row = cell.parentNode;
                        var arr = row.id.split('__');
                        var rowNumber = arr[1];
                    }

This will give you the zero-based number of the row in the grid that the item has been dropped on.

Kind regards,
Marin
the Telerik team

[Jon]

This is great for client side but I am doing this server side using onNodeDrop which accepts an object and  RadTreeNodeDragDropEventArgs.  How can I find the grid row on the server side?

[Marin]

Hi Jon,

Unfortunately the treeview does not provide such API server-side. One workaround would be to retrieve the row number on the client, store it in a hidden field and then access it on the server in the OnNodeDrop event.

Best wishes,
Marin
the Telerik team