Hi,
my question is not directly related to RadGrid but maybe someone can help me anyway.
I am using a RadGrid which is bound to a LinqDataSource. The User is able to select/deselect items within the grid.
When the user clicks the submit button the selected items are saved. To achive this, the grid has an invidible column which holds the primary keys of the items listed in the grid. After submit a list with the selected keys is passed to a method which retrievs the corresponding objects via a Linq-Query and adds them to a relation.
Now, my question is: Is it possible to get the entity object from the LinqDataSource when the user clicks the select button in the grid? It would be much more convenient to work with the objects instead of id's.
Thank you in advance for your suggestions.
Robert
1 Answer, 1 is accepted
0
Hi Robert,
Basically, you can get reference to the underlying source object for the respective grid row only in data-bound context (namely, inside the ItemDataBound handler of RadGrid). The same is true for the MS GridView control as far as I am aware.
Since the grid is not rebound when server or client selection occurs, you can either stick to the current approach with hidden column for the key field or use DataKeyNames/DataKeyValues to store/retrieve the key values from the selected rows. For more info on the second approach please review this help article.
Best regards,
Stephen
the Telerik team
Check out Telerik Trainer, the state of the art learning tool for Telerik products.
Basically, you can get reference to the underlying source object for the respective grid row only in data-bound context (namely, inside the ItemDataBound handler of RadGrid). The same is true for the MS GridView control as far as I am aware.
Since the grid is not rebound when server or client selection occurs, you can either stick to the current approach with hidden column for the key field or use DataKeyNames/DataKeyValues to store/retrieve the key values from the selected rows. For more info on the second approach please review this help article.
Best regards,
Stephen
the Telerik team
Check out Telerik Trainer, the state of the art learning tool for Telerik products.