This is a migrated thread and some comments may be shown as answers.

virtualization feature is correctly functional ?

1 Answer 90 Views
Diagram
This is a migrated thread and some comments may be shown as answers.
"By default the Virtualization feature of the RadDiagram is enabled. "

however, examples in SDK samples are UI virtualization is ineffectual.
Can I obtain a sample program that virtualization feature is correctly?

1.png : sample "layout" in SDK samples.
2.png : RadDiagram virtualizing is enabled.
3.png : generated visuals for all shapes.

1 Answer, 1 is accepted

Sort by
0
Pavel R. Pavlov
Telerik team
answered on 27 Aug 2014, 08:32 AM
Hi,

You are right for the performance of the UI virtualization of the RadDiagram. Unfortunately, we cannot create a good default virtualization algorithm that will cover every single scenario. The reason behind this is the fact that the RadDiagram can be used in many different scenarios. 

However, If you provide us with more details about your real life application and your current implementation, we will be able to suggest approach that will increase the performance of the default UI virtualization.

Pavel R. Pavlov
Telerik
 
Check out Telerik Analytics, the service which allows developers to discover app usage patterns, analyze user data, log exceptions, solve problems and profile application performance at run time. Watch the videos and start improving your app based on facts, not hunches.
 
Tags
Diagram
Asked by
Answers by
Pavel R. Pavlov
Telerik team
Share this question
or