selected row when grouping

[Zbigniew Kozłowski]

Hi,
i got a problem with getting selected row when grid is groupped. I got event on 
GridView.RowDetailsProvider.PropertyChanged
than in void:
var selectedRow = (GridViewRow)this.ListGridView.ItemContainerGenerator.ContainerFromItem(this.ListGridView.SelectedItem);
but it works only when grid is not groupped. How can i get GridViewRow from group?

[Milan]

Hello Zbigniew Kozłowski,

Could you please provide us with more information about your scenario? It might be possible to achieve the goal without even retrieving a reference to a UI row. I am interested to know why it is necessary to access UI rows?

Sincerely yours,
Milan
the Telerik team

[Zbigniew Kozłowski]

well i need two things, one is to get object, but i could achive it without a reference to UI, but second thing is to change font weight of current row

[Zbigniew Kozłowski]

so anyone can help me ?

[Milan]

Hi Zbigniew Kozłowski,

You can easily bind the FontWeight property of the row to its IsSelected or IsCurrent property. You could try the following approach:

<my:BoolToFintWeightConverter x:Key="converter"/>

<Style TargetType="telerik:GridViewRow" x:Key="rowStyle">
    <Setter Property="FontWeight"
            Value="{Binding IsSelected,
        RelativeSource={RelativeSource Self},
        Converter={StaticResource converter}}"/>
</Style>

public class BoolToFintWeightConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
    {
        var boolValue = (bool) value;

        if (boolValue)
        {
            return FontWeights.Bold;
        }
        else
        {
            return FontWeights.Normal;
        }
    }

    public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
    {
        return null;
    }
}

The last step is to assign the custom row style to the RowStyle property of the grid.

Hope this helps.

Greetings,
Milan
the Telerik team

[Steve]

Milan,
It really doesn't matter why one would want to get the GridViewRow, how can you get it?

​var selectedRow = (GridViewRow)this.ListGridView.ItemContainerGenerator.ContainerFromItem(this.ListGridView.SelectedItem);
but it works only when grid is not groupped. How can i get GridViewRow from group?

And why does the above return null?

Thanks ahead of time,
Steve

[Boris]

Hello Steve,

One possible reason for the ItemContainerGenerator.ContainerFromItem() method to stop working is for the SelectedItem to be null. You need a SelectedItem otherwise you won't get its container.

Another way to get the grouped row is to check if there are any groups and then use the ChildrenOfType<GridViewRow>() extension method on the GridView to get the selected row container. However, this will only work if the GroupRenderMode is set to Nested (this is the default mode), if its set to Flat you can use the ItemContainerGenerator.ContainerFromItem(grid.SelectedItem) method to get the selected container row container. 

private void Button1_Click(object sender, RoutedEventArgs e)
        {
            var grid = this.clubsGrid as RadGridView;

            if (grid.GroupCount > 0 && grid.SelectedItem != null)
            {
                if (grid.GroupRenderMode == GroupRenderMode.Nested)
                {
                    var groupedRows = grid.ChildrenOfType<GridViewRow>().FirstOrDefault(x => x.IsSelected);
                }
                else
                {
                    // If GroupRenderMode="Flat" use this
                    var rowContainer = grid.ItemContainerGenerator.ContainerFromItem(grid.SelectedItem) as GridViewRow;
                }
            }
        }

For more information about ChildrenOfType() method you can check Easy programmatic UI customization for WPF and Silverlight blog post.

In order to advise you better could you please provide us with more details about your scenario ?

We are looking forward to your response.


Regards,
Boris Penev
Telerik

 

 

[Steve]

Apparently the key was the GroupRenderMode!
Thanks for the quick response,
Steve