Questions on Kendo UI for jQuery Forum

2 answers

265 views

[Solved] Kendo Grid - Can Group by be more like Hierarchy

I have a grid that requests data remotely. This is where the filtering and sorting is also performed. So data will be returned in batches of 20/50/100 depending on the paging and selection.

Quite a few of the options will have datasets of >1500 records (could potentially be far more and will grow) which complicates things. The group by appears to be working fine but visually its not as easy to traverse when it is in this mode - As the first 3-6 pages could be the same group and the user may want to go digging into a few groups (or not even know they exist) making it harder to find rows.
http://demos.kendoui.com/web/grid/index.html - group by last name and shrink both... you visually scan about two items per page on average. When the data set is much larger then imagine only one group over several pages and you are looking for data.

Ideally I would like it to show as many groups as the paging is set and then page on the different groups similar to the way hierarchy would: http://demos.kendoui.com/web/grid/hierarchy.html
Going down the route of the hierarchy would be a little tedious as there may be many items grouped in the header and in different orders. So out of 8 columns 5 are likely to be commonly grouped, and could be grouped to all the different levels but a depth of three is more likely. Lastly overriding the default grouping aspect... This all could be quite complicated, but if this can be managed quite easily then im all for it.

Is there any way of changing the group by functionality to work more effectively in this scenario? Ie load the group by first and lazy load the data second depending on the opened/collapsed group(s)

Note: Loading all of the data before hand and using client side group by isnt really an option as it takes too long to process the data. It will be loading descriptions in the grid (html formatted text) so the data becomes quite hefty.

Thanks,
Matt

Grid

answered on 11 Sep 2012

0 answers

275 views

Datepicker not working after re-initialization

Hi everyone,

I am developing a single page application with Kendo UI. Since many widgets append some HTML to the <Body> the Memory consumption grows quickly when using the application (even if the widgets are no longer part of the application, e.g. closed).

To work around this, I usually remove any direct descendants of the <Body> upon unloading certain parts of my application. While this works great so far, I'm currently struggling to get the date picker widget working with this technique.

The Problem is that the date picker works fine when the application initializes it for the very first time, but after removing that date picker and creating another one some time later it won't work as intended. The Dropdown calendar is displayed but None of the links or Buttons react to clicks except for the current date on the bottom of the calendar.

Is there a way to get this working? Like I said, other widgets like Dropdown lists and Windows just work fine with my "garbage collection".

Here's a demo of the issue: http://jsfiddle.net/zwGyM/1/

Regards

DatePicker

asked on 11 Sep 2012

0 answers

347 views

How to get Selected Item's index in KendoMobileListView

Hi, I am using KendoMobileListView and I want to know how I can get the index of selected Item. My DataSource contains multiple entries and I want to be able to find out the index of selected item to show appropriate data

$('#Template').kendoMobileListView({

dataSource: EmployeeVisitsInfo,

template: '<table style="width: 100%"><tr><td><p>${a = (typeof data.Name !== "undefined") ?Name : data.LastName</td></table>',

click: function(e){

var datasource = $('#Template').data("kendoMobileListView");

var index = datasource .select().index();

var dataItem = ds.dataSource.view()[index];

console.log(index)

}

});

I dont think this is the right way to get the index of selected item because i am keep getting and error saying :

Uncaught TypeError: Object [object Object] has no method 'select'

Any Idea how I can go about doing this ? Thank you

ListView (Mobile)

asked on 11 Sep 2012

1 answer

157 views

Mobile button + MVVM + Templating - button does not renders

Following issue: MVVM model contains groups array, for each group we create a DIV with some information (fields) using source binding and data-template attribute. Each div contains a button, which is suppose to be a mobile button, but it does not render as a mobile button. I simplified my example - each div has simply a button:

<div id="test" data-role="view" data-model="viewModel">

<div data-bind="source:groups" data-template="groupsTemplate"></div>

<button data-role="button" data-bind="click:buttonClick">Add new Button</button>

</div>

<script id="groupsTemplate" type="text/x-kendo-template">

<button data-role="button" data-bind="text:caption"></button>

</script>

and a viewModel:

var viewModel = kendo.observable({

caption: "buttons",

groups:[

{name:"button1", caption:"First", error:""},

{name:"button2", caption:"Second", error:""},

{name:"button3", caption:"Third", error:""}

],

buttonClick: function(){

this.groups.push({name:"button4", caption:"Forth", error:""});

}

});

//kendo.bind($('#test'), viewModel);

new kendo.mobile.Application();

the result is: http://jsfiddle.net/S7edM/2/

Of course if I uncomment line with kendo.bind, and remove data-model attribute from root div it renders correctly, since it created mobile application on already existing DOM, but if I need to add a new button, it does not renders to mobile button.

General question: If I have different mobile components like switch, list view etc. in such "groups", which are added and removed through templates and view model, do I have any "afterAdd" and "beforeRemove" events, and is there any kendo mobile method to init newly created DOM elements?

Button (Mobile)

answered on 11 Sep 2012

1 answer

148 views

Kendo Grid update not working(JAVA + STRUTS+ tiles)

Hi Guys,

I am new to Kendo and was able to get the List on JSp in grid format but when I click on edit button, I am able to edit the data on JSP but when I click on Update , I am not able to update in database, I just want to get the data back to action class, so that I can atleast update them using JAVA code.

The only problem is with transport I guess, I dont know how to pass the URL.
Please give me a small example of code snippet how to pass control in URL if possible.

Help appreciated.

Thanks and regards,
Nitesh

Grid

answered on 11 Sep 2012

1 answer

82 views

Hovering label tag does not work for input widgets

Hello,

Hovering over a label tag which is linked to an input widgets does not work. The k-state-hover class is not applied.

Focussing does work.

Regards, Jaap

General Discussions

answered on 11 Sep 2012

1 answer

314 views

Refresh Grid from tabStrip name

I've got a tabstrip that gets data via an ajax call and loads a grid when a user clicks on the tab. While the tab is open, the user can upload a new file. In the success event of the Upload widget I want to reload the grid with the newly uploaded item shown on the list. How can I find the tab, then simulate the tab click to execute the event handler?

Thanks

TabStrip

answered on 11 Sep 2012

0 answers

168 views

Adding Dynamic items when used as form

HI,
I'm using the listview to act as a form in the same way you have in your demo's. I would like to be able to add some items dynamically to the end of the listview based on some code logic. Because this is not using a datasource as all the common items are declared in html code at designtime, how would I go about adding the extra non common items to listview.items() at runtime.

Or I could use a dataSource but then how can I specify what template each item should have when they would not all want the same template.

Thanks

ListView (Mobile)

asked on 11 Sep 2012

1 answer

226 views

How to use kendo.default.less?

What is different between kendo.default.less and kendo.default.css? And also how to use .less file in html-jquery application?

General Discussions

answered on 11 Sep 2012

7 answers

291 views

KENDO UI Performance Issue

I am getting following error multiple time while I am generating Line Chart for more than 100 items.

A script on this page is causing your web browser to run slowly. If it continues to run, your computer might become unresponsive.

ASPX Page

<%@ Page Title="Home Page" Language="C#" MasterPageFile="~/Site.master" AutoEventWireup="true"
CodeBehind="Default.aspx.cs" Inherits="KendoUIDemo._Default" %>

<asp:Content ID="HeaderContent" runat="server" ContentPlaceHolderID="HeadContent">
<script src="Scripts/jquery.min.js" type="text/javascript"></script>
<script src="Scripts/kendo.dataviz.min.js" type="text/javascript"></script>
<script src="Scripts/console.js" type="text/javascript"></script>
</asp:Content>
<asp:Content ID="BodyContent" runat="server" ContentPlaceHolderID="MainContent">

<div id="example" class="k-content" >
<div class="chart-wrapper">
<div id="chart" >
</div>
</div>
</div>
Random Data:
<asp:TextBox ID="txtNo" runat="server" Text="10" />
<asp:Button runat="server" ID="btnData" Text="Get Data" /><br />
<asp:TextBox ID="txtSerializeData" runat="server" Text="10" ClientIDMode="Static" />

<br />
<input type="button" onclick="createChart();" value="Visualize" />
<asp:DataGrid ID="gvData" runat="server" AutoGenerateColumns="false">
<Columns>
<asp:BoundColumn DataField="Date" HeaderText="Date" DataFormatString="{0:MM/dd}" />
<asp:BoundColumn DataField="onCR" HeaderText="onCR" DataFormatString="{0:f2}" />
<asp:BoundColumn DataField="offCR" HeaderText="offCR" DataFormatString="{0:f2}" />
</Columns>
</asp:DataGrid>
<script type="text/javascript">

function getArray() {

return [15.7, 16.7, 20, 23.5, 26.6];

}

function getDatafromGrid(grid, columnIndex) {
var t = "";

$(grid + " tr:has(td)").each(function () {
var col = $(this).find("td")
t = t + $(col[columnIndex]).html() + ", ";
});

return t.substring(t.indexOf(",") + 1, t.lastIndexOf(",")).split(",");

}

function createChart() {

var w = getDatafromGrid("#<%= gvData.ClientID %>", 0).length * 40;

w = (w < $(this).width()) ? $(this).width() : w;

$("#chart").width(w);
$("#chart").kendoChart({
theme: $(document).data("kendoSkin") || "default",
dataSource: {
data: eval(document.getElementById("txtSerializeData").value)
},
title: {
text: "On CR Vs off CR"
},
legend: {
position: "bottom"
},
seriesDefaults: {
type: "line",
stack: false
},
series: [{
field: "onCR",
name: "On CR"
}, {
field: "offCR",
name: "Off CR"
}],
valueAxis: {
labels: {
format: "{0}%"
}
},
categoryAxis: {
field: "Date",
rotate:90
},
tooltip: {
visible: true,
format: "{0}%"
}
});

}

// createChart();
// $(document).ready(function() {
// setTimeout(function() {
// createChart();
//
// $("#example").bind("kendo:skinChange", function(e) {
// createChart();
// });
// }, 400);
// });

</script>
</asp:Content>

//C# Code Behind

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Web.Script.Serialization;

namespace KendoUIDemo
{
public class GraphData
{
public string Date { get; set; }
public string onCR { get; set; }
public string offCR { get; set; }

}

public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{

FillData();





}

private void FillData() {

DataTable dt = new DataTable();
dt.Columns.Add("Date", typeof(DateTime));
dt.Columns.Add("onCr", typeof(Double));
dt.Columns.Add("offCr", typeof(Double));

Random r = new Random();

int range =10;

int.TryParse(txtNo.Text, out range);
List< GraphData> rows = new List<GraphData>();

for (int i = 1; i < range+1; i++)
{

GraphData g = new GraphData{Date = DateTime.Now.AddDays(i).ToString("MM/dd"), offCR = (r.NextDouble() * 100).ToString("0.00"), onCR = (r.NextDouble() * 100).ToString("0.00")};

DataRow dr = dt.NewRow();

dr["Date"] = DateTime.Now.AddDays(i).Date;
dr["onCr"] = g.onCR ;
dr["offCr"] = g.offCR;

rows.Add(g);

dt.Rows.Add(dr);

}

dt.AcceptChanges();

gvData.DataSource = dt;
gvData.DataBind();


string jsonString = JsonHelper.JsonSerializer<List<GraphData>>(rows);

JavaScriptSerializer serializer = new JavaScriptSerializer();
string jsonData = serializer.Serialize(rows);
txtSerializeData.Text = jsonData;

}

}
}

//Helper Class for Creating JSON Data

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.IO;
using System.Runtime.Serialization.Json;
using System.Text;

namespace KendoUIDemo
{

public class JsonHelper
{
/// <summary>
/// JSON Serialization
/// </summary>
public static string JsonSerializer<T>(T t)
{
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
MemoryStream ms = new MemoryStream();
ser.WriteObject(ms, t);
string jsonString = Encoding.UTF8.GetString(ms.ToArray());
ms.Close();
return jsonString;
}
/// <summary>
/// JSON Deserialization
/// </summary>
public static T JsonDeserialize<T>(string jsonString)
{
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(jsonString));
T obj = (T)ser.ReadObject(ms);
return obj;
}
}

}

Charts

answered on 11 Sep 2012