Kendo UI Grid - Model.ID

[Vivek]

I have written the following code using ASP.NET MVC3 and it's throwing me an error at the bold line(.Model(Function(model) model.id(Function(p) p.CostCentreID). It's saying that the expression does not produce a value? I thought it's asking for a primary key column only? Isn't that the case?
Please help
@ModelType IEnumerable(Of Mail.BAL.CostCentre)

@Code
    ViewData("Title") = "Index"
End Code

@(Html.Kendo().Grid(Model) _
    .Name("CostCentres") _
    .Columns(Function(modelItem) modelItem.Bound(Function(p) p.CostCentreID).Hidden) _
    .Columns(Function(modelItem) modelItem.Bound(Function(p) p.CostCentre)) _
    .Columns(Function(modelItem) modelItem.Bound(Function(p) p.Active)) _
    .ToolBar(Function(toolbar) toolbar.Create()) _
    .Groupable() _
    .Pageable() _
    .Sortable() _
    .Scrollable() _
    .DataSource(Function(datasource) datasource _
                    .Ajax() _
                    **.Model(Function(model) model.Id(Function(p) p.CostCentreID)) _**
                    .Create(Function(create) create.Action("Create", "Home")))
   )

[Rosen]

Hi Vivek,

I suspect that the error caused by the fact that the Sub should be used instead of a Function:

.Model(Sub(model) model.Id(Function(p) p.CostCentreID)) _

Regards,
Rosen
the Telerik team

[Vivek]

Hi Rosen,

That's syntax for lambda expression Function(x) x.something. It has nothing to do with actual Function/Sub in VB.NET.

[Vivek]

sorry rosen. my fault. you are right. it works now. i thought it's just a lambda expression and has nothing to do with sub/function.