or
1 answer
123 views
I have a Kendo Grid running in databound mode. When I tried to call the .saveAsPDF() method, it crashes somewhere within the framework (stack trace attached). Export to PDF works beautifully, and the Grid renders just fine.
How can I go about troubleshooting this?
How can I go about troubleshooting this?
Dimiter Madjarov
Telerik team
answered
on
12 Mar 2015
1 answer
728 views
Hello,
My Kendo Grid Template is below. If user changes radio button, I want to update dataSource. How can I do this ?
<script type="text/x-kendo-template" id="SiteTemplate">
<tr class='k-alt'>
<td>#: Name #</td>
<td>
#if(AccessType == 'Read') { #
<input type="radio" name="#: Id #" class="read" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="read" />
# } #
</td>
<td>
#if(AccessType == 'ReadWrite') { #
<input type="radio" name="#: Id #" class="readWrite" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="readWrite"/>
# } #
</td>
<td>
#if(AccessType == 'None') { #
<input type="radio" name="#: Id #" class="None" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="None" />
# } #
</td>
</tr>
</script>
My Kendo Grid Template is below. If user changes radio button, I want to update dataSource. How can I do this ?
<script type="text/x-kendo-template" id="SiteTemplate">
<tr class='k-alt'>
<td>#: Name #</td>
<td>
#if(AccessType == 'Read') { #
<input type="radio" name="#: Id #" class="read" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="read" />
# } #
</td>
<td>
#if(AccessType == 'ReadWrite') { #
<input type="radio" name="#: Id #" class="readWrite" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="readWrite"/>
# } #
</td>
<td>
#if(AccessType == 'None') { #
<input type="radio" name="#: Id #" class="None" checked="checked" />
#}else{#
<input type="radio" name="#: Id #" class="None" />
# } #
</td>
</tr>
</script>
Daniel
Telerik team
answered
on
12 Mar 2015
3 answers
366 views
Hi folks,
Two issues with grids embedded in detail rows;
1) 'undefined' data in grids embedded in detail row - the primary grid, which holds the other two tables in the detail row, uses a json array called 'mystuff', for example. The two other grids/tables, in the detail row I'm attempting to use, uses child arrays from that same 'mystuff' array.. I seem to be connecting to it, but all data comes back as 'undefined'..
So, in my columns definition, I am calling to:
..and my schema is:
is this correct? It doesn't seem like I should have to call to the child array in the template declaration.. by doing this, I get no errors on the page, but all data is 'undefined'.. I've been trying to find an example of multiple grids using the same data source with child arrays, maybe you can point me to one? I can't find anything in the dom that points to anything conclusive (other than undefined)..
2) The grids I've embedded in the details row are getting their widths from the initial grid; I've tried sizing their containers, etc.. but nothing seems to 'contain' it, lol! Ideas?
Thank you!
Two issues with grids embedded in detail rows;
1) 'undefined' data in grids embedded in detail row - the primary grid, which holds the other two tables in the detail row, uses a json array called 'mystuff', for example. The two other grids/tables, in the detail row I'm attempting to use, uses child arrays from that same 'mystuff' array.. I seem to be connecting to it, but all data comes back as 'undefined'..
So, in my columns definition, I am calling to:
template: "#=childarrayName.niftyDataField#"..and my schema is:
1.schema: {2. data: "arrayName[0].childarrayName"3.},is this correct? It doesn't seem like I should have to call to the child array in the template declaration.. by doing this, I get no errors on the page, but all data is 'undefined'.. I've been trying to find an example of multiple grids using the same data source with child arrays, maybe you can point me to one? I can't find anything in the dom that points to anything conclusive (other than undefined)..
2) The grids I've embedded in the details row are getting their widths from the initial grid; I've tried sizing their containers, etc.. but nothing seems to 'contain' it, lol! Ideas?
Thank you!
Vladimir Iliev
Telerik team
answered
on
12 Mar 2015
1 answer
323 views
I have a detailTemplate in KendoGrid. That detailTemplate again contains Grid. I want to get the modified dataSource of the detailTemplate Kendo Grid. How can I get that ? Here is my Code.
$("#grid").kendoGrid({
dataSource: dataSource,
detailTemplate: kendo.template($("#template").html()),
detailInit: detailInit,
dataBound: function () {
},
columns: [
{ field: "Id", hidden: true },
{ field: "Name", title: "Name" }
]
});
<script type="text/x-kendo-template" id="template">
<div class="SiteGrid" id="#: Id #">
</div>
</script>
function detailInit(e) {
var detailRow = e.detailRow;
detailRow.find(".SiteGrid").kendoGrid({
dataSource: dataSource,
columns: [
{ field: "Id", hidden: true },
{ field: "Name", title: "Name", width: 350 }
]
});
}
$("#grid").kendoGrid({
dataSource: dataSource,
detailTemplate: kendo.template($("#template").html()),
detailInit: detailInit,
dataBound: function () {
},
columns: [
{ field: "Id", hidden: true },
{ field: "Name", title: "Name" }
]
});
<script type="text/x-kendo-template" id="template">
<div class="SiteGrid" id="#: Id #">
</div>
</script>
function detailInit(e) {
var detailRow = e.detailRow;
detailRow.find(".SiteGrid").kendoGrid({
dataSource: dataSource,
columns: [
{ field: "Id", hidden: true },
{ field: "Name", title: "Name", width: 350 }
]
});
}
Nikolay Rusev
Telerik team
answered
on
12 Mar 2015
1 answer
1.0K+ views
Hello. I would like this to work. I know that format: 'g' will give me a number without decimals, but then it doesn't have a comma separator.
Thank you.
$('.numeric').kendoNumericTextBox({
format: "n",
decimals: 0
});
Thank you.
$('.numeric').kendoNumericTextBox({
format: "n",
decimals: 0
});
Georgi Krustev
Telerik team
answered
on
12 Mar 2015
1 answer
115 views
Hi,
If you repeat exactly these steps (example: http://dojo.telerik.com/OziZa):
- initialize grid with some data (done at load time or by pressing the "2014 data" button)
- re-initialize grid with empty data (press the "2015 data" button)
- disable sorting and add new row (press "Add row" button)
you will find that "ghost data" will emerge below the freshly inserted row. Actually, they are the rows from the first ever dataset the grid the have been initialized with.
I narrowed it down that it happens only if the current datasource is empty and the sorting is disabled. I disable sorting because I want to make sure the new row always appear on the top of the grid regardless how the grid columns were sorted beforehand.
If you repeat exactly these steps (example: http://dojo.telerik.com/OziZa):
- initialize grid with some data (done at load time or by pressing the "2014 data" button)
- re-initialize grid with empty data (press the "2015 data" button)
- disable sorting and add new row (press "Add row" button)
you will find that "ghost data" will emerge below the freshly inserted row. Actually, they are the rows from the first ever dataset the grid the have been initialized with.
I narrowed it down that it happens only if the current datasource is empty and the sorting is disabled. I disable sorting because I want to make sure the new row always appear on the top of the grid regardless how the grid columns were sorted beforehand.
Rosen
Telerik team
answered
on
12 Mar 2015
1 answer
159 views
Hello!,
I Trying to export data to excel, but this example don't working http://docs.telerik.com/kendo-ui/api/javascript/ui/pivotgrid.html#methods-saveAsExcel
If you see the console, to get error when to try get the excel file.
I need export data of the dataSource of the pivot grid to excel file.
Thanks.
I Trying to export data to excel, but this example don't working http://docs.telerik.com/kendo-ui/api/javascript/ui/pivotgrid.html#methods-saveAsExcel
If you see the console, to get error when to try get the excel file.
I need export data of the dataSource of the pivot grid to excel file.
Thanks.
Georgi Krustev
Telerik team
answered
on
12 Mar 2015
5 answers
497 views
Is there a way to make an element inside a ListView clickable without changing the state of the ListView's entire item ?
http://jsbin.com/kevoso/3/edit
In this jsbin example, if I click on the Kendo Button, the ListView item won't change it's state but if I click on the favorite icon the item will change its state.
On another subject, It seems a thread started by me a few days ago in DataSource got deleted....
http://jsbin.com/kevoso/3/edit
In this jsbin example, if I click on the Kendo Button, the ListView item won't change it's state but if I click on the favorite icon the item will change its state.
On another subject, It seems a thread started by me a few days ago in DataSource got deleted....
Petyo
Telerik team
answered
on
12 Mar 2015
4 answers
527 views
Locked property is not working with column template property in kendo grid. If I write locked:true for a column and use column template then grid is not rendering only header row of column is displaying. Columns array of grid option is given below:
01.{field: 'CHECKBOX', hidden:true, footerTemplate:'', locked:true,02. template: function(dataItem){03. if(dataItem.CHECKBOX){ return '<input type="checkbox" class="checkbox" ng-click="onClick($event)" />';}04. else{ return '';}05. }, 06. headerTemplate:'<input type="checkbox" id="headerCheckbox" ng-click="onClickAllChkBox($event)"/>', sortable: false, width: '2%', reorderable: false},07. {field:'name',headerTemplate:' NAME ', reorderable: false, footerTemplate:'合計', width: '2%', locked:true,08. template: function(dataItem){09. if(dataItem.name)10. {return '<div ng-dblclick="settingGridDblClickEventHandler($event)">'+ dataItem.name+'</div>';}11. else12. {return '<div></div>';}13. 14. }},15. {field: 'age', title: 'AGE', footerTemplate:' ', width: '8%',16. template: function(dataItem){17. if(dataItem.age)18. {return '<div ng-dblclick="settingGridDblClickEventHandler($event)">'+ dataItem.age+'</div>';}19. else20. {return '<div></div>';}21. 22. }},23. {field: 'phone', headerTemplate:' PHONE',width: '2%', footerTemplate:'',24. template: function(dataItem){25. if(dataItem.phone){ return '<a ng-click="customCellClickEventHandler($event)"><div class="tel-image"></div></a>';}26. else{ return '';}27. }28. }
Atanas Korchev
Telerik team
answered
on
12 Mar 2015
1 answer
421 views
hello.
I have just purchase Kendo UI Professional, I can't find the KendoUI.Mvc.dll in the download file : "telerik.kendoui.professional.2014.3.1411.commercial.zip"
what am I missing?
regards,
yaniv
I have just purchase Kendo UI Professional, I can't find the KendoUI.Mvc.dll in the download file : "telerik.kendoui.professional.2014.3.1411.commercial.zip"
what am I missing?
regards,
yaniv
Colleen
Telerik team
answered
on
11 Mar 2015
