IIF runs two parts

[Anders]

telerik report designer : 13.1.19.618

When I use IIF as = IIF(1 > 0, 1, 0/ 1) , it throws exception Attempted to devide by zero. I think it is a bug.

[Anders]

The expression is IIF as = IIF(1 > 0, 1, 1/0 ). 

 

ps : There is no way to edit the thread.

[Silviya]

Hi Anders,

When you use the IIf built-in function, both sides of the expression are evaluated during the processing. To avoid issues if one of the sides contains division by zero, I can suggest using ?: conditional operator instead.

Best Regards,
Silviya
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