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Kendo colour picker not accepting RGB(x,x,x) string.

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ColorPicker

This is a migrated thread and some comments may be shown as answers.

Sean asked on 15 Aug 2013, 03:26 PM

<div class="k-block">

<div class="k-header k-shadow"><span class="k-icon k-i-pencil"></span>Employee Colour</div>

<div class="editor-label">

@Html.LabelFor(x => x.BackgroundColour)

</div>

<div class="editor-field">

@(Html.Kendo().ColorPicker().Name("BackgroundColour").Palette(ColorPickerPalette.Basic).Value(Model.BackgroundColour))

@Html.TextBoxFor(x => x.BackgroundColourInput, new { @class = "editor-colour"})

</div>

<br />

<div class="editor-label">

@Html.LabelFor(x => x.TextColour)

</div>

<div class="editor-field">

@(Html.Kendo().ColorPicker().Name("TextColour").Palette(ColorPickerPalette.Basic).Value(Model.TextColour))

@Html.TextBoxFor(x => x.TextColourInput, new { @class = "editor-colour"})

</div>

<br/>

</div>

I'm using the code above to load a colour picker, the Model.BackgroundColour and Model.TextColour are strings as below:

rgb(0,255,255)

but when the form loads, the initial colour is always black, can someone tell me what I'm doing wrong please, as looking at the documentation it seems this should work. I should also point out that passing a string as below:

#00FFFF

does work.

Thanks.

Kendo colour picker not accepting RGB(x,x,x) string.

1 Answer, 1 is accepted