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Grid ClientDetailTemplate calling server action to return partial view

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daniel
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daniel asked on 17 Mar 2018, 03:41 PM

Hi,

We have a grid with a detail template containing a tabstrip - much like the demo at https://demos.telerik.com/aspnet-mvc/grid/detailtemplate .

Three tabs got their content from calling controller actions which returned different Partial views.

We do not need to show multiple tabs now - we only need to show one so do not need the tabstrip control.

How can we keep the same method of getting the detailtemplate content from a controller action partialview without the tab strip?

The data is a single model - not a listing - so not suited to a grid or listview.

Many Thanks.

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Stefan
Telerik team
answered on 20 Mar 2018, 09:31 AM
Hello, Daniel,

We have a forum post on the same subject which can be helpful:

https://www.telerik.com/forums/detail-template-and-partial-view

The main point is to make an Ajax request to the Controller action which will return the partial view on the detailInit event of the Grid and then apply that content to the container DOM element which is set in the "ClientDetailTemplateId".

Please let me know if you need more details on this matter.

Regards,
Stefan
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Stephen
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answered on 07 Jan 2020, 09:05 PM

Hi,

I effectively have the same question, and I think the linked forum post was a bit too 'high-concept' for me to follow. Could you share an example of how I could render the results of a PartialView call without using a TabStrip?

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Nikolay
Telerik team
answered on 09 Jan 2020, 02:00 PM

Hello Daniel,

I have prepared an example illustrating how loading a PartialView in a Kendo Grid could be done on a DetailInit event and placed in the detail template:

    <script type="text/x-kendo-template" id="template">
       <div class="loadPartial"></div>
    </script>

@(Html.Kendo().Grid<Sample.Models.OrderViewModel>()
	.Name("grid")
        .ClientDetailTemplateId("template")
        .Events(ev=>ev.DetailInit("onDetailInit"))
        ...

<script>
    function onDetailInit(e) {
        $.ajax({
        url: "/Home/MyCustom",
        method: 'GET',
        success: function (result) {
            e.detailCell.find(".loadPartial").html(result);
        }
    });
    }
</script>

Let me know if you have any questions.

Regards,


Nikolay
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daniel
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Stefan
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Stephen
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Nikolay
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