Rick Knicely
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Rick Knicely
asked on 23 Jul 2010, 03:50 PM
I have an application where I have several panes set up as floating only. They always appear in front of the docking area. Is there a way to make the window that contains the docking area appear in front of the panes when it is selected?
3 Answers, 1 is accepted
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Hello Rick,
Thank you for contacting us.
You can achieve the desired behavior by calling the ParentOfType<Window>() method of the floating pane at the moment. It will return the window in which is the Docking. Then, if you set its Owner property to null, the pane will go behind that window. But keep in mind that there is no way the user to use it anymore, as it will be unreachable.
Hope this information helps. If you have further questions please let us know.
Greetings,
Konstantina
the Telerik team
Thank you for contacting us.
You can achieve the desired behavior by calling the ParentOfType<Window>() method of the floating pane at the moment. It will return the window in which is the Docking. Then, if you set its Owner property to null, the pane will go behind that window. But keep in mind that there is no way the user to use it anymore, as it will be unreachable.
Hope this information helps. If you have further questions please let us know.
Greetings,
Konstantina
the Telerik team
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Rick Knicely
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answered on 28 Jul 2010, 01:06 PM
Is that true even if I call the toolwindow.focus method?
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Rick Knicely
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answered on 28 Jul 2010, 01:37 PM
Thank you,
This is the behavior that I was looking for.
It's still a pane, however since I have set it to floating only I don't care that it is no longer "usable" or dockable.