6 Answers, 1 is accepted
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Richard Slade
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answered on 07 Feb 2011, 06:13 PM
Hi Ryno,
You should be able to do this I believe with the ExcelCellFormatting event.
Please can you try the following
let me know if that helps. If not, i'll try and put a full sample together
Richard
You should be able to do this I believe with the ExcelCellFormatting event.
Please can you try the following
AddHandler export.ExcelCellFormatting, AddressOf Export_ExcelCellFormatting Private Sub Export_ExcelCellFormatting(ByVal sender As Object, ByVal e As ExcelCellFormattingEventArgs) If e.GridColumnIndex = Me.RadGridView1.Columns("ColumnName").Index And e.GridRowIndex > -1 Then Dim sb As New System.Text.StringBuilder(Me.RadGridView1.Rows(e.GridRowIndex).Cells(e.GridColumnIndex).Value.ToString()) e.ExcelCellElement.Render(sb) End IfEnd Sublet me know if that helps. If not, i'll try and put a full sample together
Richard
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Richard Slade
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answered on 07 Feb 2011, 06:20 PM
Hi Ryno,
I'm trying some various tests on this and it seems like this may not be the solution. I'll come back to you as soon as I can.
Richard
I'm trying some various tests on this and it seems like this may not be the solution. I'll come back to you as soon as I can.
Richard
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Johan
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answered on 07 Feb 2011, 06:22 PM
Ah, thanks Richard. I was just busy trying out your first suggestion :-)
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Richard Slade
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answered on 07 Feb 2011, 06:24 PM
Hi,
Ok, only a slight update. I believe that this will work for you
Hope that helps
Richard
EDIT// Note you might need to handle looking for NULL values too.
R
Ok, only a slight update. I believe that this will work for you
Private Sub Export_ExcelCellFormatting(ByVal sender As Object, ByVal e As ExcelCellFormattingEventArgs) If e.GridColumnIndex = Me.RadGridView1.Columns("ColumnName").Index And e.GridRowIndex > -1 Then e.ExcelCellElement.Data.DataItem = Me.RadGridView1.Rows(e.GridRowIndex).Cells(e.GridColumnIndex).Value.ToString() End IfEnd SubHope that helps
Richard
EDIT// Note you might need to handle looking for NULL values too.
R
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Johan
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answered on 07 Feb 2011, 06:44 PM
Awesome, that is exactly what I was looking for.
Thanks Richard!
Thanks Richard!
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Richard Slade
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answered on 07 Feb 2011, 07:26 PM
Excellent! Glad that worked for you.