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Detail View dinamically

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elll
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elll asked on 12 Apr 2012, 03:51 PM
Hi
I have a ListView in a tabstrip with a button like the Sushi Demo and i want that when i click on the button the application open the detail view in the same view.
How can i do this?
thanks Elios 

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d2uX
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answered on 12 Jul 2012, 12:40 PM
Just trying to accomplish the exact same thing.
However just looking at the demo code isnt really self explaining. Especially when trying to do this in MVVM-style.

Can't somebody give a simple clean MVVM-Tutorial on such a basic thing?
I dont really know if what I wrote is how it's supposed to be ^^'
Here's what I did so far:

defining a viewModel with a dataSource
var productDS = new kendo.data.DataSource({
    transport: {
        read: {
            url: '/get.php',
            dataType: 'jsonp',
            data: {
                type: 'products'
            }
        }
    },
    pageSize: 10,
    serverpaging:true
})
 
var productViewModel = kendo.observable({
    productList: productDS
});

defining a function for fetching the details (taken from the sushi-demo)
function showProductDetail(e) {
    var view = e.view;
     
    productDS.fetch(function() {
        var model = view.model,
            item = productDS.get(view.params.id);
        model.set("product", item)
    });
}

and finally getting everything together in the template
<script id="productListTpl" type="text/x-kendo-template"">
   <a
         class="details-link"
         data-role="listview-link"
         href="\#productDetail?id=${id}">
         <h2>${name}</h2>
    </a>
</script>
note the ?id= in the href! this specifies the id your detail records are loaded from

Hope this helps and really would appreciate a clean Tut ;)
Thx so far, amazing (frame)work :)
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