Child Form Location

[Victoria F]

I have MDI frame. .NET C# WinForms.
In the MDI frame I have a main window that contains ListBox. Depend on selected item from the ListBox a Child Form suppose to be opened with parameters. Everything working file except :  I want Child Form to be opened next to the ListBox on the main form.
So  I'm trying to set  x, y location position properties of the Child Form. Does not work.
Every form opens ... looks like in cascading positions. ( I noticed it because I tried to open and close 5 - 7 forms and I saw that every other form was opened a little aside from the previous).
I need every form to be opened at the same location. What should I do for it?
Please , help...

Thank you ,
Victoria.

[Richard Slade]

Hi Victoria,


hope you're well.
you need to get the screen position of the cursor and pass that to the form.

For exmaple:

In the form that you want to place next to the ListBox

private Point m_Location;
public DialogForm(Point location)
{
    InitializeComponent();
    m_Location = location;
}
private void DialogForm_Load(object sender, EventArgs e)
{
    this.Location = m_Location;
}

In the ListBox Selection Changed

private void radListControl1_SelectedIndexChanged(object sender, Telerik.WinControls.UI.Data.PositionChangedEventArgs e)
{
    if (radListControl1.SelectedIndex == 2)
    {
        Point scrPos = this.PointToScreen(radListControl1.Location);
        DialogForm form = new DialogForm(scrPos);
        form.Show();
    }
}

Hope this helps, but let me know if you have any questions
Richard

[Victoria F]

Richard,
This works absolutely amazing!!
Thanks a lot!
Victoria.

[Richard Slade]

Hi Victoria,

Glad I could help. Please remember to mark as answer.
All the best
Richard