Unterminated string error

[Jagdish]

Hi,

I get the error "Kendo.Mvc.Infrastructure.Implementation.FilterParserException: Unterminated string" when I try to filter using the character "&"

Here is the URL of the query: 
localhost/Documents?Grid-sort=WorkOrder.ShortTitle-asc&Grid-page=1&Grid-pageSize=10&Grid-group=&Grid-filter=WorkOrder.ShortTitle~contains~'&'

[FilterParserException: Unterminated string]
Kendo.Mvc.Infrastructure.Implementation.FilterLexer.<TryParseString>m__17F(Char character) +164
Kendo.Mvc.Infrastructure.Implementation.FilterLexer.Read(Func`2 predicate, StringBuilder result) +57
Kendo.Mvc.Infrastructure.Implementation.FilterLexer.TryParseString(String& string) +180
Kendo.Mvc.Infrastructure.Implementation.FilterLexer.Tokenize() +155
Kendo.Mvc.Infrastructure.Implementation.FilterParser..ctor(String input) +39
Kendo.Mvc.Infrastructure.FilterDescriptorFactory.Create(String input) +54
Kendo.Mvc.UI.DataSourceRequestModelBinder.BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) +202
Kendo.Mvc.UI.Grid`1.ProcessDataSource() +187
Kendo.Mvc.UI.Grid`1.WriteHtml(HtmlTextWriter writer) +574
Kendo.Mvc.UI.WidgetBase.ToHtmlString() +86
Kendo.Mvc.UI.Fluent.WidgetBuilderBase`2.ToHtmlString() +22
System.Web.HttpUtility.HtmlEncode(Object value) +38
System.Web.WebPages.WebPageBase.Write(Object value) +75

I am using kendo version 2013.1.514.340

Thanks

[Vladimir Iliev]

Hi Jagdish,

I tried to reproduce the problem locally but to no avail – everything is working as expected on our side. Could you please provide runable project where the issue is reproduced? This would help us pinpoint the exact reason for this behavior.

Kind Regards,
Vladimir Iliev
Telerik

[Jagdish]

Hi,

I used the code sample for Export Excel. I modified the web.config to use sql server.
 I can reproduce the error. Please see the screenshot attached and the project files.

Thanks

[Atanas Korchev]

Hi,

 The & is a special character used to separate query string parameters. You need to encode the filter value like this:

href = href.replace(/filter=([^&]*)/, 'filter=' + (encodeURIComponent(requestObject.filter) || '~'));

Regards,
Atanas Korchev
Telerik