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I have tried using this command (as per instructions in one of your blogs) to launch file open dialog immediately upon loading of ImageEditor with no success
imageEditor.Commands.Open.Execute(null);
I have put it in Loaded and ImageEditorLoaded functions, it does not work.
How should I do it?
imageEditor.Commands.Open.Execute(null);
I have put it in Loaded and ImageEditorLoaded functions, it does not work.
How should I do it?