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i need to use row template and sortable features together. But it is not working. Can somebody help me how do i fix this?
My sample code is below: 
###############################################


<script src="path/to/jquery"></script> 
        <script src="path/to/kendo/all/js"></script> 
<script src="../../content/shared/js/people.js"></script>
        <link href="../../../styles/kendo.common.min.css" rel="stylesheet" />
<div id="example" class="k-content">
            <table id="people">
                <thead>
                    <th>Id</th>
                    <th>First Name</th>
                    <th>Last Name</th>
                    <th>Title</th>
                    <th>Age</th>
                </thead>
                <tbody>
                    <tr>
                        <td></td>
                        <td></td>
                        <td></td>
                        <td></td>
                        <td></td>
                    </tr>
                </tbody>
            </table>
            <script id="template" type="text/x-kendo-template">
                <tr class="asdf">
                     <td>#= Id #</td>
                    <td>#= FirstName #</td>
                    <td>#= LastName #</td>
                    <td>#= Title #</td>
                    <td>#= Age #</td>
                </tr>
            </script>
            <script>
                $(document).ready(function() {
                    //initialize dropdownlist components
$("#people").kendoGrid({
dataSource: {data: createRandomData(500)},
height: 200,
sortable: true,
rowTemplate: kendo.template($("#template").html())
});
   
                });
            </script>




#############################################


Thank you!
Jesus
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 answered on 06 Apr 2012
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I've integrated a Kendo splitter into SharePoint 2010.  I see the following error in the firebug console:
kendo.ui.Resizable is not a constructor
http://domain/sites/TestDeployment/Pages/_layouts/1033/STYLES/KendoUI/Web/kendo.splitter.js
Line 931

I also find that I'm unable to access my existing splitter using
var splitter = $("#mainArea").data("kendoSplitter");
where #mainArea is the ID of the div where I attached the splitter.  When I try this, I see an error in the firebug console indicating that "splitter is undefined".
$("#mainArea").height() returns the height of the div, and there is a splitter there that otherwise works.

Any ideas?  Please let me know if I can provide any other information that may help.

Thanks.
Bruce
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 asked on 06 Apr 2012
0 answers
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Hello.
I understand that you want to provide developers with complete framework for building html5 apps. But with the last release where you have added your own MVVM implementation we've got into troubles.
We have our own objects and can't inherit them from kendo.ObserableObject. We was adding them into kendo.Grid and evething worked. But now kendo automatically tries to wrap our objects into its own ObserableObject/ObserableArray objects. As our object have cyclic references wrapping process fails with StackOverflow exception. I wonder what's your position about using kendo with "foreign" viewModels (which weren't created by kendo.obsersable): do you suppose it to work or not? Tnx.
Sergei
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 asked on 05 Apr 2012
2 answers
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If I have a object with properties bound to a grid: A, B, C, D (Object Order), but columns as displayed (D, C, B, A) by changing the columns value on the gird when an item is added it seems to be added in the grid column order, not the object order, so I get a very interesting collection:

A, B, C, D
A, B, C, D
D, C, B, A

Where the first two are items retrieved from a database and the last one is added via the add button on the grid.

Needless to say when I send the data to the web service, it really doesn't like it.

I don't know if this is a Javascript problem, a WCF problem, a Kendo MVVM problem or a Kendo Grid problem. If I rearrange the object on the WCF side to list in the order I want to display things. All seems fine.

What is the best way to handle this?

Thanks
Randy
Randy
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 answered on 05 Apr 2012
4 answers
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Hello,

I have downloaded for testing Kendo Mobile and tried to create a simple login page but failed.
My login page has a very strange layout problem that I can't solve.

Currently I have no idea why it is impossible to create a simple login page with Kendo Mobile or what I'm doing wrong.

The code of the login page is here:

<!DOCTYPE html>
<html>
<head>
        <meta charset="utf-8" />
        <meta name="viewport" content="width=600, initial-scale=1, maximum-scale=1">
        <meta name="apple-mobile-web-app-capable" content="yes"/>
        <script type="text/javascript" src="Scripts/jquery-1.7.1.min.js"></script>
        <script type="text/javascript" src="Scripts/jquery.json-2.3.min.js"></script>
        <script type="text/javascript" src="Scripts/knockout-2.0.0.js"></script>
 
        <script type="text/javascript" src="Scripts/kendo/kendo.mobile.min.js"></script>
        <script type="text/javascript" src="Scripts/kendo/plugins/console.js"></script>
        <link href="Styles/kendo/kendo.mobile.all.min.css" rel="stylesheet" />
</head>
<body>
     
<div data-role="view" data-layout="login" data-title="Login">
    <div data-role="header">
        <div data-role="navbar">
            <span data-role="view-title"></span>
        </div>
    </div>
    <div data-role="footer">
        <div data-role="tabstrip">
            <a data-icon="globe" href="#overview-cities">Login</a>
            <a data-icon="contacts" href="#overview-contacts">Contacts</a>
        </div>
    </div>
    <div id="container">
        <span>Main header</span>
        <div>
            <label for="Username">Username</label>
            <input id="Username" name="Username" type="text" />
        </div>
        <div>
            <label for="Password">Password</label>
            <input id="Password" name="Password" type="password" />
        </div>
        <div class="clear">
        </div>
        <div>
            <label for="SelectedLanguage">SelectedLanguage</label>
            <select id="SelectedLanguage" name="SelectedLanguage">
                <option value="da-DK">dansk (Danmark)</option>
                <option value="en-GB">English (United Kingdom)</option>
                <option value="fi-FI">suomi (Suomi)</option>
                <option value="de-DE">Deutsch (Deutschland)</option>
                <option value="nb-NO">norsk, bokmål (Norge)</option>
                <option selected="selected" value="ru-RU">русский (Россия)</option>
                <option value="sv-SE">svenska (Sverige)</option>
            </select>
        </div>          
        <div>
            <a input="button" data-role="button">Login</a>
        </div>
    </div>
</div>
 
<script type="text/javascript">
    window.kendoMobileApplication = new kendo.mobile.Application();
</script>
</body>
</html>

I have also attached a simple project with this page to illustrate the problem.

Can anybody help me?
Did anyone try to create a mobile login form with Kendo mobile?

Thank you very much.

Vladimir
Kamen Bundev
Telerik team
 answered on 05 Apr 2012
2 answers
332 views
I have a view with a listview showing some menu items generated from a web service data source.

Each menu item has an onclick which causes the listview to be rebinded with new menu items.

At this point I also want to change the title of the view. How do I do this?

I tried:
document.getElementById("myView").setAttribute("data-title", myNewTitle)
but this only works when the page is first displayed.

Thanks
Keith
Keith Avery
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 answered on 05 Apr 2012
0 answers
202 views

Hi

We are working with the Kendo UI and are quite new to MVVM. We were trying out the following scenario and came across an issue which is as below.

We have a checkbox list on our page along with 2 listboxes (say listbox1 and listbox2).

The checkboxlist is a consolidated list of all the items from both the ListBoxes. Initially when no items are checked on the checkboxlist, all the items appear on the listbox1. The items when checked on the checkboxlist should move to listbox2 and should be removed from listbox1.

There is also a textbox and button ['Add Item'] using which we can add values to listbox1 (correspondingly these will appear as unchecked on the checkboxlist).

The problem:

The viewModel does not get refreshed on the check and uncheck events of the checkboxes. Because of this, the listboxes do not get updated with their  respective items.
However the viewModel refreshes the listboxes when a new item is added using the textbox and 'Add Item' button.

Please follow the JSFiddle link for code reference:  http://jsfiddle.net/umeshkrishna/eqWK2/9/

I am also attaching screen- shots as aides.

Looking  forward to a speedy reply.


Thanks
Umesh

 

 

 

 

 

 

 

 

 

 

Umesh
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 asked on 05 Apr 2012
0 answers
144 views
This is not so much a question as it is a quick tip to help those with similar needs.

I want to open a row's detail simply by clicking a selection, as opposed to having to click on the arrow cell. As part of the kendoGrid initialization, I added the following code:
,   change         : function() {
        var grid = this;
 
        grid.select().each(function() {
            grid.collapseRow(grid.tbody.find("tr.k-master-row"));
            grid.expandRow(grid.tbody.find("tr.k-state-selected"));
        });
    }

This will first close all open detail rows, then open the one you've selected.
Mike
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 asked on 05 Apr 2012
1 answer
177 views
Hi,

The grid loses the selection (highlighting) on sorting, is there any way to retain the selection on sort or default selection to first row after sort is done?

J
David
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 answered on 05 Apr 2012
1 answer
304 views
Hi there,

Just wanted to let you know that I think I found a bug that the grid footer does not scroll horizontally like the header does. Here's an example http://jsfiddle.net/mtrichards26/zCZGF/6/

Here's what I did locally to make this work (in the grid's _footer and _wrapFooter functions, changes preceded with //CHANGE)
_footer: function() {
           var that = this,
               aggregates = that.dataSource.aggregates(),
               html = "",
               footerTemplate = that.footerTemplate,
               options = that.options;
 
           if (footerTemplate) {
               html = $(that._wrapFooter(footerTemplate(aggregates || {})));
 
               if (that.footer) {
                   var tmp = html;
 
                   that.footer.replaceWith(tmp);
                    
                   that.footer = tmp;
               } else {
                   if (options.scrollable) {
                       that.footer = options.pageable ? html.insertBefore(that.wrapper.children("div.k-grid-pager")) : html.appendTo(that.wrapper);
                        
                      //CHANGE: Have scroll event move .k-grid-footer-wrap                      
                      var scrollables = that.footer.children('.k-grid-footer-wrap');
 
                      that.content.bind('scroll', function () {
                           scrollables.scrollLeft(this.scrollLeft);
                   });
 
                   } else {
                       that.footer = html.insertBefore(that.tbody);
                   }
               }
           }
       },
 
       _wrapFooter: function(footerRow) {
           var that = this,
               html = "",
               columns = that.columns,
               idx,
               length,
               groups = that.dataSource.group().length,
               column;
 
           if (that.options.scrollable) {
               //CHANGE: Add extra div with .k-grid-footer-wrap
               html = $('<div class="k-grid-footer"><div class="k-grid-footer-wrap"><table cellspacing="0"><tbody>' + footerRow + '</tbody></table></div></div>');
               that._appendCols(html.find("table"));
 
               return html;
           }
 
           return '<tfoot>' + footerRow + '</tfoot>';
       },


Also, I thought I posted this yesterday but didn't see it today so if its a duplicate please feel free to delete this post.

Thanks,
Matt
Dimo
Telerik team
 answered on 05 Apr 2012
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