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Kendo UI for jQuery Forum
1 answer
235 views
Hello,

I'm currently trying to use KendoUI to implement a simple slider in a survey for a client.
Therefore, I wouldn't require the 500+kb of JS from the kendo.web.min.js and I would like to integrate the element with the minimum required dependencies.

Based on your documentation below, the slider widget only requires 4-5 script files to work :
http://docs.kendoui.com/getting-started/javascript-dependencies#slider-and-rangeslider

I'm trying to integrate the slider widget on a blank page using the specified script files, but the drag and drop functionality doesn't work.
I always get the following issue : "TypeError: v is not a constructor" in the file "kendo.draganddrop.min.js"

Here is the html portion :
<input id="slider" class="balSlider" value="0" />
 
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/kendo.core.min.js"></script>
<script type="text/javascript" src="js/kendo.binder.min.js"></script>
<script type="text/javascript" src="js/kendo.draganddrop.min.js"></script>
<script type="text/javascript" src="js/kendo.slider.min.js"></script>
<script type="text/javascript">
  (function () {
    //wait for DOM availability
    $(document).ready(function () {
      //create slider
      $("#slider").kendoSlider();
    });
  })();
</script>
I also attached a zip archive with the POC source.

Is there a missing dependency in your file list?


Thank you.
Hristo Germanov
Telerik team
 answered on 20 Nov 2012
0 answers
237 views
var dd = elem.kendoDropDownList({
                            dataTextField: "Name",
                            dataValueField: "ID",
                            value: attr.value,
                            select: function(e) {
                                var item = this.dataItem(e.item.index());
                                console.log(item.value); // UNDEFINED
                            },
                            dataSource: source
                        }).data("kendoDropDownList");
Andrej
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 asked on 20 Nov 2012
6 answers
126 views
I have an issue with a Kendo UI scroller. I have posted it at the Kendo forums here :http://www.kendoui.com/forums/mobile/general-discussions/issue-with-scroller-in-android.aspx

Looking forward to some guidance!
Jan-Dirk
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Rank 1
 answered on 20 Nov 2012
2 answers
196 views
Hi, i have a problem with the grid,
we need hide command with a condition and block to edition cell with same condition.

my cod of command

{ command: {text: "Guardar", click: change }, title: "Guardar"}

function change

function change(){
    
var concepto = "";
var saldo = "";
var venta = "";
var oper = "";
var prepago = "";
var castigo = "";
var utilidad = "";
var grid = this;
 
 
grid.select().each(function(){
var dtim = grid.dataItem($(this));
concepto += ""+dtim.concepto;
saldo += ""+dtim.saldo;
venta += ""+dtim.venta;
oper += ""+dtim.oper;
prepago += ""+dtim.prepago;
castigo += ""+dtim.castigo;
utilidad += ""+dtim.utilidad;
});
}
how hide and block for edition cell when concepto == 'Total'


Help me please!


Alexander Valchev
Telerik team
 answered on 20 Nov 2012
1 answer
154 views
@(Html.Kendo().Grid(Model).Name("gridName")
.Columns(columns =>
      {
          columns.Bound(o => o.Name);
          columns.Bound(o => o.Surname);
          columns.Bound(o => o.Timespan);
      }).DataSource(d=>d.Ajax().Model(m=>m.Id("Name")).ServerOperation(false))
      .Filterable().ColumnMenu().Sortable()
      )

The code above makes my grid to sort and filter without GET request to server, but it loads content twice - first becuease of ...Grid(Model)... and secondly beacause of ....DataSource(d=>d.Ajax().Model(... and column with Timespan shows [object Object] after 'second' load. How to correct it?
Atanu
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Rank 1
 answered on 20 Nov 2012
0 answers
190 views
I had this working at one point for a 3.5 application. I am not trying it on an asp.net mvc 4.0 application. It is using bundles. The problem I had before was that either my .css or my .jss files had to be in a particular order. I'm not positive if it is the order or if I'm missing something.

In my _layout.cshtml I have:
 @Styles.Render("~/Content/css")
    @Styles.Render("~/Content/kendo")
    @Scripts.Render("~/bundles/jquery")
    @Scripts.Render("~/bundles/kendo")

in BundlesConfig.cs I have:
bundles.Add(new StyleBundle("~/Content/css").Include(
                    "~/Content/site.css"));

 bundles.Add(new StyleBundle("~/Content/kendo").Include(
                    "~/Content/kendo/2012.3.1114/kendo.common.*",
                    "~/Content/kendo/2012.3.1114/kendo.black.*",
                    "~/Content/kendo/2012.3.1114/kendo.dataviz.*"));

bundles.Add(new ScriptBundle("~/bundles/jquery").Include(
                        "~/Scripts/jquery-1.8.2.js"));

 bundles.Add(new StyleBundle("~/Content/kendo").Include(
                    "~/Content/kendo/2012.3.1114/kendo.common.*",
                    "~/Content/kendo/2012.3.1114/kendo.black.*",
                    "~/Content/kendo/2012.3.1114/kendo.dataviz.*"));


Thanks
Dennis
Dennis
Top achievements
Rank 1
 asked on 19 Nov 2012
0 answers
100 views
It looks like the search pattern in the "contains" logic searches something along the line of %some value%

Is there any way I can get to search by %some%value% without having to implement a custom filter?

I have a working example of the custom filter but I just want to be sure that there isn't some way this can be done that is already in the grid filter. I have several grid columns that will need this logic.

Thanks!
David
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Rank 1
 asked on 19 Nov 2012
0 answers
148 views
I am finding that, no matter what I set the Step value to, pressing the up and down arrow keys adds or subtracts exactly double the step value (clicking on the spinners respects the step setting). Is this by design?
Mark
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Rank 1
 asked on 19 Nov 2012
0 answers
122 views
My controls are widgets, so if I define my template in the markup it appears twice on the page...

Is there a way with the MVVM that I can move the template out to my JS and still bind it?...like a data-bind="template: markup, source: data" or something?

Steve
sitefinitysteve
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Iron
Iron
Veteran
 asked on 19 Nov 2012
0 answers
92 views
When i change the url of a tab on my tabstrip the document.ready code for that page does not get called, how can i ensure that it does? 
Andrew
Top achievements
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 asked on 19 Nov 2012
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