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How to mock events when using Future Mocking?

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answered on 02 May 2014, 06:56 AM

Hello,

the main issue I'm struggling with is that when you do:

Mock.Raise(xxx,xxx)

then you cannot put .IgnoreInstance() because the return type of the Raise() method is different from the Arrange() so I cannot use Future Mocking together with Raise().

What I want to do is something like:

// Arrange

TestedClass testedClass = new TestedClass();

Mock.Arrange(() => new Timer()).DoNothing();

// Act

Mock.Raise(() => new Timer().Elapsed += null, new ElapsedEventArgs()).IgnoreInstance();

That way I will be able to test the eventHandler of the timer inside the TestedClass.

Anyway we are using Timers.Timer just in case it helps.

Regards.

answered on 07 May 2014, 06:45 AM

Hello Ignacio,

I'm sorry for keeping you waiting for so long.

You still need an instance on which to raise the event. Raising the event on all existing timers is likely impractical. I suggest that you use the arrangement on the new expression to get the instance on which to raise the event, like so:

// Arrange

Timer timer = null;

Mock.Arrange(() => new Timer()).DoInstead((Timer thisTimer) => timer = thisTimer);

// Act

// first, do the thing that creates the timer

Timer.Do();

// we now have a reference to the timer from the above DoInstead clause

Mock.Raise(() => timer.TheEvent += null);

In the above code I get the reference to the created timer using future constructor mocking. Then, I can raise the event on the instance regularly.

I hope this is enough to get your test running.

Cheers!
Stefan
Telerik

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