This is a migrated thread and some comments may be shown as answers.
[Solved] Error OnStart Up

1 Answer 257 Views
Getting Started
This is a migrated thread and some comments may be shown as answers.
This question is locked. New answers and comments are not allowed.
Fakhru asked on 30 Aug 2009, 10:14 PM
I got error when using OpenAccess on my ASP.NET MVC apps, here the stact trace:
    
            Telerik.OpenAccess.OpenAccessException was unhandled by user code 
        
              Message="Unable to create RelationalKeyGeneratorFactory instance OpenAccessRuntime.Relational.sql.HighLowRelationalKeyGenerator+Factory" 
        
              Source="Telerik.OpenAccess" 
        
              CanRetry=false 
        
              StackTrace: 
        
                   at Telerik.OpenAccess.SPI.Backends.ThrowException(Exception e) 
        
                   at Telerik.OpenAccess.RT.ExceptionWrapper.Throw() 
        
                   at OpenAccessRuntime.storagemanager.StorageManagerFactoryBuilder.createSmfForURL() 
        
                   at OpenAccessRuntime.storagemanager.StorageManagerFactoryBuilder.createStorageManagerFactory() 
        
                   at OpenAccessRuntime.DataObjects.PersistenceManagerFactoryImp.createStorageManagerFactory() 
        
                   at OpenAccessRuntime.DataObjects.PersistenceManagerFactoryBase.init() 
        
                   at OpenAccessRuntime.DataObjects.PersistenceManagerFactoryImp.init() 
        
                   at OpenAccessRuntime.DataObjects.PersistenceManagerFactoryImp..ctor(IDictionary properties, Object classloader) 
        
                   at OpenAccessRuntime.DataObjects.PersistenceManagerFactoryImp.getPersistenceManagerFactory(IDictionary props) 
        
                   at OpenAccessRuntime.DataObjects.BootstrapPMF.getPersistenceManagerFactory(IDictionary props) 
        
                   at Telerik.OpenAccess.RT.Helper.getPersistenceManagerFactory(IDictionary props) 
        
                   at Telerik.OpenAccess.RT.DatabaseAdapter.AssertPersistenceManagerFactory(String usr, String password, Boolean open) 
        
                   at Telerik.OpenAccess.RT.DatabaseAdapter.GetObjectScope(TransactionProvider provider) 
        
                   at Telerik.OpenAccess.RT.DatabaseAdapter.GetObjectScope() 
        
                   at Telerik.OpenAccess.Database.GetObjectScope() 
        
                   at _9JuliSoftware._Default.get_UniqueScope() in C:\Documents and Settings\F8R\My Documents\Visual Studio 2008\Projects\9julisoftware\Default.aspx.cs:line 32 
        
                   at _9JuliSoftware.Controllers.HomeController.Index() in C:\Documents and Settings\F8R\My Documents\Visual Studio 2008\Projects\9julisoftware\Controllers\HomeController.cs:line 21 
        
                   at lambda_method(ExecutionScope , ControllerBase , Object[] ) 
        
                   at System.Web.Mvc.ActionMethodDispatcher.Execute(ControllerBase controller, Object[] parameters) 
        
                   at System.Web.Mvc.ReflectedActionDescriptor.Execute(ControllerContext controllerContext, IDictionary`2 parameters) 
        
                   at System.Web.Mvc.ControllerActionInvoker.InvokeActionMethod(ControllerContext controllerContext, ActionDescriptor actionDescriptor, IDictionary`2 parameters) 
        
                   at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClassa.<InvokeActionMethodWithFilters>b__7() 
        
                   at System.Web.Mvc.ControllerActionInvoker.InvokeActionMethodFilter(IActionFilter filter, ActionExecutingContext preContext, Func`1 continuation) 
        
              InnerException: System.InvalidCastException 
        
                   Message="Unable to cast object of type 'Factory' to type 'OpenAccessRuntime.Relational.RelationalKeyGeneratorFactory'." 
        
                   Source="Telerik.OpenAccess.Runtime" 
        
                   StackTrace: 
        
                        at OpenAccessRuntime.Relational.RelationalKeyGeneratorFactoryRegistry.getFactory(String name) 
        
                   InnerException:
Best Regards,
Fakhru Rahman
[Solved] Error OnStart Up

1 Answer, 1 is accepted
