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Hi
I have a Hashtable. It represent a word translation.
The Key is the country and the value is the translated word.
MyHashtable.Add("EN","Day") ;
MyHashtable.Add("DL","Tag") ;
MyHashtable.Add("FR","Jour") ;
How can i create dynamically 3 Colums for each value ? The header of the colum may be the Key.
There is maybe another way to resolve my data construction.
Thank you
I have a Hashtable. It represent a word translation.
The Key is the country and the value is the translated word.
MyHashtable.Add("EN","Day") ;
MyHashtable.Add("DL","Tag") ;
MyHashtable.Add("FR","Jour") ;
How can i create dynamically 3 Colums for each value ? The header of the colum may be the Key.
There is maybe another way to resolve my data construction.
Thank you
7 Answers, 1 is accepted
0
Hello,
Vlad
the Telerik team
Can you post a bit more info about your scenario? If you want to localize the grid please check this demo for more info.
Best wishes,Vlad
the Telerik team
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answered on 21 Oct 2010, 03:29 PM
Hello
I will not use Hashtable. I will use Dictionary.
My probleme looks like this : http://www.telerik.com/community/forums/silverlight/gridview/binding-to-a-dictionary.aspx
My problem is less difficult : i had to use Dictionary<string, string> and not Dictionary<string, object>
Do I had to use DictionaryConverter in my case ?
I'm trying to adapt your example
Thank you
Mathieu
I will not use Hashtable. I will use Dictionary.
My probleme looks like this : http://www.telerik.com/community/forums/silverlight/gridview/binding-to-a-dictionary.aspx
My problem is less difficult : i had to use Dictionary<string, string> and not Dictionary<string, object>
Do I had to use DictionaryConverter in my case ?
I'm trying to adapt your example
Thank you
Mathieu
0
Hello,
Vlad
the Telerik team
If you want dynamic data binding in Silverlight it will be better to try our lightweight DataTable.
All the best,Vlad
the Telerik team
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answered on 22 Oct 2010, 05:11 PM
Hi
I succeded in displaying my data.
I have used the bindingtodictionary.zip technics.
But i can't modify these data into my gridView.
Here is my colums creation :
foreach (string languageKey in currentDataContext.LanguageList)
{
dataColumn = new GridViewDataColumn() { Header = languageKey, DisplayIndex = columIndex, UniqueName = languageKey };
binding = new Binding();
binding.Path = new PropertyPath("TranslationList");
binding.Mode = BindingMode.TwoWay;
binding.Converter = new DictionaryConverter(languageKey);
dataColumn.DataMemberBinding = binding;
grid.Columns.Add(dataColumn);
columIndex++;
}
Can you help me please ?
Or can you simply modify the bindingtodictionary.zip .
Thank you
Mathieu
I succeded in displaying my data.
I have used the bindingtodictionary.zip technics.
But i can't modify these data into my gridView.
Here is my colums creation :
foreach (string languageKey in currentDataContext.LanguageList)
{
dataColumn = new GridViewDataColumn() { Header = languageKey, DisplayIndex = columIndex, UniqueName = languageKey };
binding = new Binding();
binding.Path = new PropertyPath("TranslationList");
binding.Mode = BindingMode.TwoWay;
binding.Converter = new DictionaryConverter(languageKey);
dataColumn.DataMemberBinding = binding;
grid.Columns.Add(dataColumn);
columIndex++;
}
Can you help me please ?
Or can you simply modify the bindingtodictionary.zip .
Thank you
Mathieu
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answered on 28 Oct 2010, 02:00 PM
Hello
It's is possible to have the bindingtodictionary.zip example in which i could modify values ?
Thank you
Mathieu
It's is possible to have the bindingtodictionary.zip example in which i could modify values ?
Thank you
Mathieu
0
Hi,
Vlad
the Telerik team
I still believe that you should use our lightweight DataTable instead plain dictionary. Have you tried the DataTable?
Best wishes,Vlad
the Telerik team
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answered on 28 Oct 2010, 02:14 PM
Hi
I have to create dynamicaly some of my colums but not all colums.
It's it possible with DataTable?
Mathieu
I have to create dynamicaly some of my colums but not all colums.
It's it possible with DataTable?
Mathieu
