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8 answers
300 views
i'm migrated my project to Kendo UI v2014.3.1316 (previously kendo v2014.2.1008) and the mobile popover widget doesn't instantiate anymore. With previous version it work fine..
My sample code:< div id="popUser" kendo-mobile-pop-over="popUser" k-popup='{}'>
< /div >error:
TypeError: Cannot read property 'element' of undefined
at new D.extend.init (http://localhost:25586/Scripts/kendo/kendo.all.min.js:27:19741)
at new a.extend.init (http://localhost:25586/Scripts/kendo/kendo.all.min.js:27:25449)
at new u.extend.init (http://localhost:25586/Scripts/kendo/kendo.all.min.js:27:31527)
at HTMLDivElement. (http://localhost:25586/Scripts/kendo/kendo.all.min.js:10:2045)
at Function.jQuery.extend.each (http://localhost:25586/Scripts/jquery/jquery-1.11.1.js:383:23)
at jQuery.fn.jQuery.each (http://localhost:25586/Scripts/jquery/jquery-1.11.1.js:136:17)
at mt.plugin.e.fn.(anonymous function) as kendoMobilePopOver
at m (http://localhost:25586/Scripts/kendo/kendo.angular.min.js:9:1274)
at o (http://localhost:25586/Scripts/kendo/kendo.angular.min.js:9:1737)
at w.directive.directive.directive.directive.directive.directive.directive.directive.directive.link.pre (http://localhost:25586/Scripts/kendo/kendo.angular.min.js:9:13712)error screenshot from chrome:
http://i60.tinypic.com/2vtozf6.pngany suggestion?
thanks
Petyo
Telerik team
 answered on 14 May 2015
0 answers
201 views
I am using Method 2 for binding my data to a flat file as shown here:
Binding to flat data
<div id="tree"></div>
<script>
var flatData = [
  { id: 1, parent: null, text: "Item 1" },
  { id: 2, parent: null, text: "Item 2" },
  { id: 3, parent: null, text: "Item 3" },
  { id: 4, parent: null, text: "Item 4" },
  { id: 5, parent: 1, text: "Item 1.1" },
  { id: 6, parent: 1, text: "Item 1.2" },
  { id: 7, parent: 1, text: "Item 1.3" },
  { id: 8, parent: 3, text: "Item 3.1" },
  { id: 9, parent: 3, text: "Item 3.2" },
  { id: 10, parent: 5, text: "Item 1.1.1" },
  { id: 11, parent: 5, text: "Item 1.1.2" },
  { id: 12, parent: 5, text: "Item 1.1.3" }
];
 
// tree for visualizing data
$("#tree").kendoTreeView({
  dataSource: {
    transport: {
      read: function(options) {
        var id = options.data.id || null;
 
        options.success($.grep(flatData, function(x) {
          return x.parent == id;
        }));
      }
    },
    schema: {
      model: {
        id: "id",
        hasChildren: function(x) {
          var id = x.id;
 
          for (var i = 0; i < flatData.length; i++) {
            if (flatData[i].parent == id) {
              return true;
            }
          }
          return false;
        }
      }
    }
  }
})
</script>
Now, however, I need to add some icons to differentiate the kind of file (Folder, excel, PDF, etc)
I have found a series of icons that I think would work would work at:
jQuery icons styling example
I just am not sure how to add the desired icons (or their references) into the JSON or set the TreeView up to show them.
All of the examples that I have found show both the data and the icon hard coded and I need to know how to have the icons in the JSON and for the tree to then generate them.
I have tried adding a JSON field called "image" and at a different time one called "icon" - neither seemed to work.
So, how would I set the icons up and show them?

TIA,
Bob Mathis
Bob
Top achievements
Rank 2
 asked on 13 May 2015
2 answers
1.1K+ views

Hi guys,

I've setup a datepicker, it's showing the selected date properly but I'm having a hard time in sending it towards my controller in the same format it's showing. For some reason it seems to be reverting back from dd/MM/yyyy to MM/dd/yyyy.

Below my script used.

01.<script>
02.    var datepicker;
03.    $(document).ready(function () {
04.        datepicker = $("#datepicker").data("kendoDatePicker");
05. 
06.        $("#btnToReport").click(function () {
07.            $.post("/ShiftReport/ViewReport?datepicker=" + datepicker.value().toLocaleString(), function (data, status) {
08.                if (status === "success") {
09.                    $("#main-content").html(data);
10. 
11.                }
12.            });
13.        });
14.    });
15.</script>

Daniel
Telerik team
 answered on 13 May 2015
4 answers
112 views

Hi all,

we are implementing a grid using asp.net mvc and aspx pages. We are encountering a couple of problems using templates because it seems

that Visual Studio 2013 does not recognize the object implementation correctly. The error returned by Visual Studio is the CS1525:Invalid expression term ')'..  This is our code with the comments..

<%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/SiteEnvironment.Master" Inherits="System.Web.Mvc.ViewPage<MyApp.Models.EnvTblModel>" %>

<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
</asp:Content>
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">
<h2>Environment List</h2>
<%:
Html.Kendo().Grid<MyApp.Models.EnvTblModel>()
    .Name("Grid")
    .BindTo((IEnumerable<MyApp.Models.EnvTblModel>)ViewBag.EnvironmentList)
    .Columns(colList =>
        {

            foreach (var runCol in ViewBag.colSchLst)
            {  

colList.Bound(runCol.TBS_BOUND_FIELD_NAME).Title(runCol.TBS_COLUMN_NAME);
            }
            colList.Bound(p =>
p.TBG_FILLER_CHK01).Template(p =>
            {       /*VISUAL STUDIO GIVES THE ERROR CS1525: Invalid expression term ')' HERE .. */
                %>
                    <strong><%: p.TBG_FILLER_CHK01 %></strong>   //THIS BLOCK SEEMS NOT RECOGNIZED 
                <%
            });
        });
%>
</asp:Content>
<asp:Content ID="Content3" ContentPlaceHolderID="FeaturedContent" runat="server">
</asp:Content>

 

Thank you in advance for your help..

 

Regards

 

 

 

Rosen
Telerik team
 answered on 13 May 2015
1 answer
148 views
<div>
        @using (Html.BeginForm("SignIn", "Account",  FormMethod.Post,  new { @class = "form-horizontal", role = "form", autocomplete="off" }))
        {
            @Html.AntiForgeryToken()
            <dl class="dl-horizontal">
                <dt>
                    @Html.LabelFor(x => x.UserName)
                </dt>
                <dd>
                    @Html.TextBoxFor(x => x.UserName, new {@id="user_name", @disabled="true"})
                </dd>
                <dt>
                    @Html.LabelFor(x => x.Password)
                </dt>
                <dd>
                    @Html.PasswordFor(x => x.Password, new {@id="password", @autocomplete="off" , @disabled="true"})
                </dd>
                <dt>
                    @Html.LabelFor(x => x.StoreNum)
                </dt>
                <dd>
                    @(Html.Kendo().DropDownListFor(x => x.StoreNum)
                    .DataSource(ds => ds
                    .Read(r=> r.Action("GetStoreList", "Account")))
                    .HtmlAttributes(new {@id="store_list",@disabled="true" })
                    )
                </dd>
                <dd>
                    <input type="submit" value="Log in" class="btn btn-default" disabled="true" id="login_button" />
                </dd>
            </dl>
           
        }
    </div>

 

I have a drop down list that reads data from my controller.  I need to enable fields and a button in the UI after the data is loaded into the dropdownlist.  How can I do this?

Kiril Nikolov
Telerik team
 answered on 13 May 2015
1 answer
148 views

Hello,

I would like to catch the grid request i.e. when sorting or grouping via server and execute on some modal dialog when OK clicked. As I understand on requestStart we can perform some actions, but further execution flow will proceed. In my case I would like to display login dialog + some other login selections and if login succeeds, continue with the request. Is it possible?

Thanks

Daniel
Telerik team
 answered on 13 May 2015
5 answers
390 views
Hi,

I have a problem with decimal separators when doing inline editing.
Right now I have a solution that works, but I need more than two digits after the decimal separator:

The model:
[DataType("number")]
public double Percent
{
    get { return (double)Math.Round(source.Percent, 5); }
    set { source.Percent = (decimal)value; }
}

The view:
.Columns(columns =>
{
    columns.Bound(c => c.Percent).Title(Resource.Percent).Format("{0:n5}");

Setting the culture:
var c = '@System.Globalization.CultureInfo.CurrentCulture.ToString()'
kendo.culture(c);

The DataType=number, in the model, formats the inline input box the correct way.
The "Format("{0:n5}")", in the view, formats the number correctly in the grid.
There is no problems when updating the model (model-state is valid), but I need higher precision.

thanks.
Rosen
Telerik team
 answered on 13 May 2015
3 answers
354 views
How do I format the width of the page-sizes button on a grid ??

This is what I have:

.Pageable(p =>
    p.Refresh(true)
    .ButtonCount(10)
    .PageSizes(new[] { 10, 25, 100, 200, 1000 })
    .Input(true)
    )

I have tried the following:
.k-pager-wrap .k-dropdown{
    width: 280px;
}

var ddl = $('[data-role="dropdownlist"]').data("kendoDropDownList");
ddl.list.width(100);

-which only change the width of the dropdown list.
How to change the width of the button itself ??
Thanks.
Bryan
Top achievements
Rank 1
 answered on 12 May 2015
2 answers
4.5K+ views

Hi,

How do I add a default filter on a kendo.grid ?

I have a filter on a boolean, which is working just fine, but I would like TRUE to be the selection by default.

I am quite sure that I have done this before and then removed it again, and now I can't remember howto :-(

I'am aware, that server side operations require more than just setting the default filter selection, but once I have figured out how to set the filter in the view, then I figure out the rest.

So, how to set default filter in the view ??

Thank you in advance.

Jacob
Top achievements
Rank 1
 answered on 12 May 2015
4 answers
97 views

It is probably easy as you might say it is. But the fact remains is that I can not find the solution anywhere.

 Here is my code:

public ActionResult Edit([DataSourceRequest] DataSourceRequest gridRequest, Sub editSub)
        {
            if (ModelState.IsValid) 
            {
                Sub subToUpdate = db.Subs.FirstOrDefault();
                subToUpdate.SFirst = editSub.SFirst;
                subToUpdate.SLast = editSub.SLast;
                subToUpdate.SEmail = editSub.SEmail;
                db.SaveChanges();
            }

            return Json(new[] { editSub }.ToDataSourceResult(gridRequest, ModelState));
        }

Every time I modify a different row the first row gets overwritten. I assume that I nee to specify the ID in here: db.Subs.FirstOrDefault(); 

I cannot find how to?

Dimiter Madjarov
Telerik team
 answered on 12 May 2015
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