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UI for ASP.NET MVC Forum
1 answer
783 views

I am getting a warning in the browser console (Chrome) with kendo date picker.

 

I am not setting date format to "yyyy-MM-dd". I have even tried to set up date format in the cshtml page for the kendo date picker.

@(Html.Kendo().DatePickerFor(m => m.StartDate)
           .Name("StartDate")
           .Format("MM/dd/yyyy")
           .Value(Model.StartDate))

Is this a default date format with date pciker? How can I change it?

Georgi Krustev
Telerik team
 answered on 02 Jul 2015
3 answers
231 views

Is it possible to define the grid attributes/properties in the MVC controller rather than the view to simplify the view at all?  I am currently evaluating Kendo before deciding whether or not to migrate from Infragistics IgniteUI.  

Infragistics IgniteUI igGrid allows you to define a GridModel (their object type) instance in your controller and pass it to the View which allows a much simpler bit of syntax in the view similar to:

Controller code:

    Public Function IGGridModel() As Infragistics.Web.Mvc.GridModel

        Dim grdModel As GridModel = New Infragistics.Web.Mvc.GridModel.GridModel()

        With grdModel
             . ID = ....

            .columns ....

             etc, etc

         End With

         Return grdModel

    End Function

 

View Code:

   <div ....  whatever>

        @Html.Infragistics().Grid(Model.IGGridModel)
  </div>

 

 

Kiril Nikolov
Telerik team
 answered on 02 Jul 2015
1 answer
194 views

I need to check all the child checkboxes when I'll check the parent checkbox. For example, in the attached file I need to check all the checkboxes (11M, 11MPRICE, 15M, 23M....) when I'll click BINS. And another case is if all checkboxes are selected then parent checkbox should be checked automatically. How can I do these?

 

 Thanks in advance.

Alexander Popov
Telerik team
 answered on 02 Jul 2015
2 answers
333 views

I am using Kendo UI for ASP.Net MVC 2015.2.   I have defined a grid using razor syntax as follows:

 

                                                                Html.Kendo().Grid(Of NameValue)() _
                                                                .Name("grdTerms") _
                                                                .DataSource(Function(ds) ds.Ajax() _
                                                                .Batch(True) _
                                                                .ServerOperation(False) _
                                                                .Read(Function(r) r.Data(UIHelper.ToJSON(Model.MyNameValues)))) _
                                                                .Columns(Sub(c)
                                                                             c.Bound("Name").Title("My Name")
                                                                             c.Bound("Value").Title("My Value")
                                                                         End Sub) _
                                                                .Pageable(Function(pager) pager.Input(True).Numeric(False).Info(True).PreviousNext(True).Refresh(True).PageSizes(True)) _
                                                                .Scrollable() _
                                                                .Render()

 

The generated JQuery for the grid in the view shows that the datasource has JSON data assigned, yet no data appears in the grid.  The view code is generated as follows:

 

<div class="k-widget k-grid" id="grdTerms"><div class="k-grid-header"><div class="k-grid-header-wrap"><table><colgroup><col /><col /></colgroup><thead class="k-grid-header"><tr><th class="k-header" data-field="Name" data-index="0" data-title="My Name" scope="col"><span class="k-link">My Name</span></th><th class="k-header" data-field="Value" data-index="1" data-title="My Value" scope="col"><span class="k-link">My Value</span></th></tr></thead></table></div></div><div class="k-grid-content" style="height:200px"><table><colgroup><col /><col /></colgroup><tbody><tr class="k-no-data"><td colspan="2"></td></tr></tbody></table></div><div class="k-pager-wrap k-grid-pager"><a class="k-link k-pager-nav k-state-disabled k-pager-first" data-page="1" href="#" title="Go to the first page"><span class="k-icon k-i-seek-w">seek-w</span></a><a class="k-link k-pager-nav k-state-disabled" data-page="0" href="#" title="Go to the previous page"><span class="k-icon k-i-arrow-w">arrow-w</span></a><span class="k-pager-input k-label">Page<input class="k-textbox" type="text" value="1" />of 1</span><a class="k-link k-pager-nav k-state-disabled" data-page="2" href="#" title="Go to the next page"><span class="k-icon k-i-arrow-e">arrow-e</span></a><a class="k-link k-pager-nav k-state-disabled k-pager-last" data-page="1" href="#" title="Go to the last page"><span class="k-icon k-i-seek-e">seek-e</span></a><span class="k-pager-sizes k-label"><select><option>5</option><option>10</option><option>20</option></select>items per page</span><a class="k-pager-refresh k-link" href="/Test/Test" title="Refresh"><span class="k-icon k-i-refresh">Refresh</span></a><span class="k-pager-info k-label">No items to display</span></div></div><script>
jQuery(function(){jQuery("#grdTerms").kendoGrid({"columns":[{"title":"My Name","field":"Name","encoded":true},{"title":"My Value","field":"Value","encoded":true}],"pageable":{"input":true,"numeric":false,"refresh":true,"pageSizes":[5,10,20],"buttonCount":10},"messages":{"noRecords":"No records available."},"dataSource":{"type":(function(){if(kendo.data.transports['aspnetmvc-ajax']){return 'aspnetmvc-ajax';} else{throw new Error('The kendo.aspnetmvc.min.js script is not included.');}})(),"transport":{"read":{"url":"","data":[{"Name":"Test 1","Value":"1","Tag":""},{"Name":"Test 2","Value":"2","Tag":""},{"Name":"Test 3","Value":"3","Tag":""}]},"prefix":""},"pageSize":10,"page":1,"total":0,"schema":{"data":"Data","total":"Total","errors":"Errors","model":{"fields":{"Value":{"type":"object"},"Tag":{"type":"string"},"Name":{"type":"string"},"Dirty":{"type":"boolean"},"SupressEvents":{"type":"boolean"}}}},"batch":true}});});
</script>

 

As can be seen, the dataSource has data assigned - "data":[{"Name":"Test 1","Value":"1","Tag":""}, .... yet the grid renders empty.

What am I missing?

 

 

Rosen
Telerik team
 answered on 01 Jul 2015
1 answer
109 views
I have a menu that I want to add tooltips to. So far, I have added a tooltip, but it is for the entire menu and I would like different tooltips for each menu item.

Is this possible and if so, how would I do it?

Here is the code I have so far:
<div style="background-color: #41526e; float: left">
    @(Html.Kendo()
          .Menu()
          .Name("Menu")
          .Items(items =>
          {
              items.Add().Text("Home").Action("Index", "Home").ImageUrl(Url.Content("~/Images/Home.png"));
              items.Add().Separator(true);
              items.Add()
                   .Text("Search")
                   .Action("Search", "Catalog")
                   .ImageUrl(Url.Content("~/Images/Search.png"));
              items.Add().Separator(true);
              items.Add()
                   .Text("First Action")
                   .Action("FirstAction", "Catalog")
                   .ImageUrl(Url.Content("~/Images/Promote.png"));
              items.Add().Separator(true);
              items.Add()
                   .Text("Second Action")
                   .Action("SecondAction", "Catalog")
                   .ImageUrl(Url.Content("~/Images/Promote.png"));
              items.Add().Separator(true);
              items.Add()
                   .Text("Subscription Stuff")
                   .Action("Index", "Subscription");
              items.Add().Separator(true);
              items.Add()
                   .Text("Schedule Stuff")
                   .Action("CreateSchedule", "Subscription");
          })
          .Orientation(MenuOrientation.Vertical)
    )
 
    @(Html.Kendo()
        .Tooltip()
        .For("#Menu")
        //.Filter("button")
        .AutoHide(true)
        .Content("Greetings, Puny Earthling! This is a tooltip for your edification.")
        .Position(TooltipPosition.Top)
        .Width(200)
    )
 
</div>

 

TIA,

Bob

Iliana Dyankova
Telerik team
 answered on 01 Jul 2015
4 answers
911 views

Hello,

 we are trying to export a Grid to Excel. This works fine, but since we are using percentage based width for some columns, this percentage ("30%") gets turned into a pixel count (30px), which in turn makes the Excel column way too small.

 

Is there a way to set a better width, or an automatic "Be as big as you need to be in Excel" for the export?

 

@(Html.Kendo().Grid<BusinessObjectLayer.BusinessObjects.CategoryOfCostBusinessObject>()
    .Name("CategoryGrid")
    .Columns(columns =>
    {
        columns.Bound(p => p.Title).Width("30%");
        columns.Bound(p => p.Rate).Width(70);
        columns.Bound(p => p.Description).ClientTemplate("#: convertHtmlString(Description, 50)#");
        columns.Command(command => { command.Edit().Text(" "); command.Destroy().Text(" "); }).Width(88);
    })
    .ToolBar(toolbar => { toolbar.Create().Text("Add Category"); toolbar.Excel().HtmlAttributes(new { @class = "pull-right" }).Text(" Export to Excel"); })
    .Excel(excel => excel
        .FileName("Categories.xlsx")
        .Filterable(true)
        .AllPages(true)
        .ProxyURL(Url.Action("ExcelExport", "Category"))
    )

Thanks for your help,

Klaus

Dimiter Madjarov
Telerik team
 answered on 01 Jul 2015
1 answer
294 views

Hi,

i'm using Kendo.Mvc version 2015.1.429.440 (Q2 2015), but when I use Locked(true) to a column,

it doesn't get frozen. I'd like to know:

- what is doing wrong in my code

@(Html.Kendo().Grid(Model)
         .Name("grid")
                 .Columns(columns =>
                     {
                         columns.Bound(typeof(string), Model.Columns[0].ColumnName.ToString()).Locked(true);
                         
                         for(int p=1;  p< Model.Columns.Count-1; p++)
                         {
                             columns.Bound(typeof(string), Model.Columns[p].ColumnName.ToString())
                                 .Width(150)
                                 .Encoded(false);
                                 //.ClientTemplate("<img src='" + Url.Content(column.ColumnName.ToString()) + "' />")
                         }
                     })                   
        )

 

thanks for help in advance.

Radoslav
Telerik team
 answered on 01 Jul 2015
1 answer
1.4K+ views

Hi team,

 How to change kendo grid property  using jquery. i want change property of kendo Grid. 

if (Some condition)

{

        var grid = $("#GridGlobalNewRequest").data("kendoGrid");
        grid.dataSource.options.schema.model.fields.StartCompany.editable = true;
        grid.dataSource.options.schema.model.fields.IsRead.editable = true;

}

else

{

         var grid = $("#GridGlobalNewRequest").data("kendoGrid");

        grid.dataSource.options.schema.model.fields.StartCompany.editable = false;

        grid.dataSource.options.schema.model.fields.StartCompany.defaultValue = "9990"; // Default Value

}

 

Thanks

Senthilkumar N

Boyan Dimitrov
Telerik team
 answered on 01 Jul 2015
3 answers
600 views

Hi

How do insert a control within a Panel.

As an example below with the Panel Getting Started I would have the text "Testing" and then a Kendo.button underneath ?

 

<h3>Telerik UI for ASP.NET MVC PanelBar</h3>
<br />
 
@(Html.Kendo().PanelBar()
    .Name("IntroPanelBar")
    .Items(items =>
    {
        items.Add()
            .Text("Getting Started")
            .Selected(true)
            .Expanded(true)
            .Content(@<text>
                Testing

    //button here

            </text>);
 
        items.Add()
            .Text("Add NuGet packages and jump-start your coding")
            .Content(@<text>
                <p style="padding:0 1em">NuGet makes it easy to install and update free libraries and tools.
                <a href="http://go.microsoft.com/fwlink/?LinkId=245153">Learn more…</a></p>
            </text>);
        items.Add()
            .Text("Find Web Hosting")
            .Content(@<text>
                <p style="padding:0 1em">You can easily find a web hosting company that offers the right mix of features
                and price for your applications.
                <a href="http://go.microsoft.com/fwlink/?LinkId=245157">Learn more…</a></p>
            </text>);
    })
)

 

​

​

Alexander Popov
Telerik team
 answered on 30 Jun 2015
1 answer
170 views

dear community,

 I'm facing the following issue right now:

 within my TreeView it should be possible, that every node and all its children can be copied within the same tree. Therefore I've setup a button which calls a function that tries to copy the node + its children.

The function looks like this:

function CopyTreeViewItems() {
        var treeview = $('#treeview').data('kendoTreeView');
        var selectedNode = treeview.select();
 
        var data = treeview.dataItem(selectedNode);
 
        var newData = {
            id: GenerateGuid(),
            Name: data.Name + "tmp"
        };
 
        treeview.insertAfter(newData, selectedNode);
        var parentItem = treeview.dataItem(treeview.findByText(newData.Name)); //<--- this part is returning 'undefined'
 
            if (data.hasChildren) {
                var children = data.children.data();
 
                for (var i = 0; i < children.length; i++) {
                    var add = { id: GenerateGuid(), Name: children[i].Name };
                    treeview.append(add, parentItem);
                }
            }
}

The parent node is copied without any problems. If there are children of a parent node I'm not able to append them to the corresponding new parent.

Any advices?

Kind regards

Tom

Thomas
Top achievements
Rank 2
 answered on 30 Jun 2015
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