Questions on Telerik Document Processing Forum

1 answer

106 views

Documentation

Where can I find the documentation for SpreadProcessing?

http://www.telerik.com/help/wpf/introduction.html Does not have anything yet.

I'm a user of UI for WPF.

Thank you.

SpreadProcessing

answered on 05 Mar 2014

12 answers

892 views

How to extract a file

Hi

I not figure out how to save a (large) binary file to disk from a zip-Package back to a file.

Thanks for help

ZipLibrary

answered on 28 Jan 2014

15 answers

521 views

Zip of PDF document doesn't work

Hi,

I'm trying to zip a PDF document but something goes wrong.
This is the code I use

MemoryStream compressedStream;

ZipPackage package;

MemoryStream sourcestream = new MemoryStream();

RadDocument document = this.CreateDocument(TileViewmodel);

this.PrepareDocument(document);

PdfFormatProvider provider = new PdfFormatProvider();

provider.Export(document, sourcestream);

compressedStream = new MemoryStream();

package = ZipPackage.Create(compressedStream);

package.AddStream(sourcestream, "WindowPeristedData");

Right before I add a PDF file of 7MB, the length of the compressedStream variable is 22 (bytes I think). After the AddStream the size is 142. I don't think that is correct. The sourcestream I add has a lenghth of 7.085.200. You can't zip an 7MB file into a 142 byte file.

What am I doing wrong?

Kind regards,

Jan Buskens.

ZipLibrary

answered on 24 Dec 2013

3 answers

135 views

Encrypt ZipLirbary

Hi,

is it possible to encrypt and decrypt a ZipLirbary which is created with the RadZipLirbary? How to?

Thanks
best Regards
Rene

ZipLibrary

answered on 29 Nov 2013

1 answer

153 views

ZipPackage filename encoding issue

Hey together,

I've got a little problem with the ZipPackage in the Telerik.Windows.Zip library.

I'm developing in a Silverlight environment (Silverlight Business Application). On the server side I zip a user specified amount of files (which are stored in a Microsoft SQL database).

At first a little code snippet:

MemoryStream ms = new MemoryStream();

byte[] zip = null;

using ( ZipPackage zipfile = ZipPackage.Create(ms) ) {

foreach ( var kvp in files ) {

zipfile.AddStream(new MemoryStream(kvp.Value), kvp.Key, ZipCompression.Default, DateTime.Now);

}

zip = new byte[(int) ms.Length];

ms.Seek(0, SeekOrigin.Begin);

ms.Read(zip, 0, (int) ms.Length);

ms.Dispose();

}

return zip;

As you can see, I store the ZipPackage in a MemoryStream. After the "using" code block I return the content of the MemoryStream (ms) back to the client side of my application (the above procedure is called due to an InvokeOperation). On the client side, the returned byte array will be stored under a user specified filename in the local file system. This works really proper, but after opening the stored zip file, I see, that filenames (containing german umlauts like ä, ö, ü) are not well encoded.

For example:
A filename in the database is called "Aufsätze.docx". After storing this file with this filename in the zippackage and save the file on my hard disk, the filename is called "Aufs+ñtze.docx".

I've tried a lot with encoding ... default, utf8, etc. but nothing works.

Do you have an idea, what else I can do or try? If you need more information or code snippets, please let me know it.

Kind regards,
Chris

ZipLibrary

answered on 01 Nov 2013

3 answers

201 views

Filename in ZipPackageEntry not Contains german umlauts

Hi,

i got a question using the ZipLibrary.

We got a .zip file with about 20 files zipped.

Some of the filenames contains german umlauts like ä,ö,ü ....

Now, when using the ziplibrary the filenames which got german umlauts are incorrect.

Here is the function to get the files.

Dim fname As String = System.IO.Path.Combine(System.Configuration.ConfigurationManager.AppSettings("GlobalUploadPath"), Filename)

Dim fs As New FileStream(fname, FileMode.Open, FileAccess.Read)

Try

Using package = ZipPackage.Open(fs)

Dim allEntries As List(Of ZipPackageEntry) = package.ZipPackageEntries

For Each entry As ZipPackageEntry In allEntries

Dim filename As String = System.IO.Path.GetFileNameWithoutExtension(entry.FileNameInZip.ToLower)

-->> wrong filenames in entry.FileNameInZip

If tableList.Contains(filename) Then

' Reading the Data

End If

Next

End Using

Any hint's ?

thank you

ZipLibrary

answered on 09 Aug 2013

1 answer

115 views

Stream compression not working

Hi,

we have requirement to generate zip file from list of images and allow it to download in Silverlight.
All images are stored on remote machine(\\192.168.1.7\\abc\\\abc\year\month\1234\1234.jpg).
so I have implemented functionality to get the list of images and passed it to wcf service as an argument
and it returns list of byte array.
I have implemented the below code to create the zip file from list of stream.

busyIndicator.IsBusy = true;

if (ListPic.Count > 0)

{

//Save zip File

SaveFileDialog dialog = new SaveFileDialog();

dialog.Filter = "Zip File | *.zip";

bool? dialogResult = dialog.ShowDialog();

if (dialogResult == true)

{

using (ZipPackage zipPackage = ZipPackage.Create(dialog.OpenFile()))

{

foreach (PictureFile pic in ListPic)

{

Stream picStream = new MemoryStream(pic.PictureStream);

zipPackage.AddStream(picStream, System.IO.Path.GetFileName(pic.PictureName),ZipCompression.Deflated,DateTime.Now);

}

busyIndicator.IsBusy = false;

this.DialogResult = false;

}

else

{

busyIndicator.IsBusy = false;

this.DialogResult = false;

}

In above code I have used to deflate compression to compress stream but it always returns the size and compression not works.
Is there any more configuration required for compression to work?

Thanks
Rahul

ZipLibrary

answered on 17 Jul 2013

3 answers

305 views

Can ZipPackage zip folders?

Does anyone know if the ZipPackage can accept a folder or set of folders and build a valid zip file from them? I haven't seen any examples or documentation on this.

ZipLibrary

answered on 21 May 2013

5 answers

396 views

Zipping in a memory stream

I am trying to zip files to a memory stream but the stream content is always 0 even if the stream length seem correct.

MemoryStream ms = new MemoryStream();

Telerik.Windows.Zip.ZipPackage z = null;

z = Telerik.Windows.Zip.ZipPackage.Create(ms);
z.Add(fi.FullName);

Data = null;

System.IO.BinaryReader reader = new System.IO.BinaryReader(ms);
Data = new byte[(int)ms.Length];
reader.Read(Data, 0, (int)ms.Length);
ms.Close();

--> Data contains only "0".

Can you pls advise ?

Thanks

Patrick

ZipLibrary

answered on 17 Apr 2013

1 answer

154 views

GZip Support

Hello telerik!

Is GZip supported now?
Thanks,
Tim.

ZipLibrary

answered on 01 Mar 2013