Row headers columns size on print

[Alex Dybenko]

Hi,

when I print PivotGrid - all Row headers columns have same size, is it possible to print them similar size like on the screen? Like for datacells columns, see attached

Alex

[Hristo]

Hi Alex,

Thank you for writing.

Indeed, the row headers are not printed with the desired width. I have logged this issue in our feedback portal and I have also added a vote for it on your behalf. You can subscribe to the item and be notified its status changes here: FIX. RadPivotGrid - row headers width should be respected when the pivot is being printed. I have also updated your Telerik points.

The issue will be fixed with our upcoming release scheduled for the end of the month. Until then you would need to use a custom PivotGridPrintStyle class and override its Initialize method: 

private void PrintPivotGrid()
{
    MyPivotGridPrintStyle style = new MyPivotGridPrintStyle();
    style.LayoutType = PivotLayout.Tabular;
    this.radPivotGrid1.PrintStyle = style;
    this.radPivotGrid1.PrintPreview();
}

public class MyPivotGridPrintStyle : PivotGridPrintStyle
{
    public override void Initialize()
    {
        base.Initialize();

        FieldInfo fiColumnWidths = this.GetType().BaseType.GetField("columnWidths", BindingFlags.Instance | BindingFlags.NonPublic);
        List<int> columnWidths = (List<int>)fiColumnWidths.GetValue(this);
        RadPivotGridElement pivotGrid = (RadPivotGridElement)this.GetType().BaseType.GetField("pivotGrid", BindingFlags.Instance | BindingFlags.NonPublic)
                                                                                    .GetValue(this);

        for (int i = 0; i < pivotGrid.RowDescriptorsArea.Children.Count; i++)
        {
            RadElement descriptor = pivotGrid.RowDescriptorsArea.Children[i];
            columnWidths[i] = descriptor.Size.Width;
        }
    }
}

I hope this helps. Please let me know if you have further questions.

Regards,
Hristo Merdjanov
Telerik by Progress

[Alex Dybenko]

Thanks Hristo, works fine!

 

Alex