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Know group.Key in a AggregateFuncion

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Salvador
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Salvador asked on 13 Nov 2012, 07:29 AM
I like to know waht group.key call to the aggregate function.
It's possible?

Thanks.

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Dimitrina
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answered on 13 Nov 2012, 03:32 PM
Hi,

I am not sure what your question is. Would you please explain better what is the result you would like to achieve?

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Didie
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Salvador
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answered on 13 Nov 2012, 04:46 PM
Well, when i group, the system go to the AggregateFunction.
This is the function for example.

    public static class AgregateFunction
    {      public static String F_Entregados<TSource>(IEnumerable<TSource> source)
        {
              HERE, I WANT TO KNOW WHAT GROUP COLUMS "FIRE" THE FUNCTION
              FOR EXAMPLE     COMPANY -> STATE

              AND OTHER QUESTION IS THAT, I HAVE IN  source   ALL DATA IN THE GROUP (COMPANY -> STATE)

              CAN I ACCES HERE TO ALL THE DATA WITHOUT GROUP??

         }
    }


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Dimitrina
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answered on 14 Nov 2012, 03:00 PM
Hello,

Unfortunately such an information about the Groups is not available with the AggregateFunction method when it is invoked. What do you mean by : "CAN I ACCES HERE TO ALL THE DATA WITHOUT GROUP??", do you mean all the Data bound to the GridView?

All the best,
Didie
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Salvador
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answered on 14 Nov 2012, 03:14 PM

 public  static String F_Confirmados<TSource>(IEnumerable<TSource> source)

In source only come the data that is in the group, but not all of the dadagridview. 
I want to acces to all.

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Dimitrina
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answered on 14 Nov 2012, 04:07 PM
Hi,

You could access the data bound to the GridView through the RadGridView.ItemsSouce collection or from the bound collection directly.

Regards,
Didie
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Salvador
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answered on 14 Nov 2012, 05:08 PM
For example
I have 3 category
    - A, B, C

i want that my agregate function say
 Group  A     COUNT(A) = 23      COUNT(A) / COUNT(B)      COUNT(A) / COUNT(C) 

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Dimitrina
Telerik team
answered on 15 Nov 2012, 10:21 AM
Hi,

I would suggest you to check this help article on more information for the different options to define a custom aggregate.

All the best,
Didie
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