Hello,
Previously i am using SL4 and i have property class Telerik.Windows.Controls.GridView.ColumnFilterDescriptor and have property FieldFilter.FieldName.
Now i have convert SL4 to SL4 and i am using Telerik.Windows.Controls.GridView.IColumnFilterDescriptor class and we did not found the property FieldFilter.FieldName.
Can you please let me know how to access the fieldFilter.fieldname in SL5 version telerik Grid,. We are using the version :2013.3.1016.1050 ?
Please let me know your feedback as soon as possible,
Previously i am using SL4 and i have property class Telerik.Windows.Controls.GridView.ColumnFilterDescriptor and have property FieldFilter.FieldName.
Now i have convert SL4 to SL4 and i am using Telerik.Windows.Controls.GridView.IColumnFilterDescriptor class and we did not found the property FieldFilter.FieldName.
Can you please let me know how to access the fieldFilter.fieldname in SL5 version telerik Grid,. We are using the version :2013.3.1016.1050 ?
Please let me know your feedback as soon as possible,
6 Answers, 1 is accepted
0
Hello Padman,
Please follow Column Filter Descriptors help article for more information.
Regards,
Yordanka
Telerik
Please follow Column Filter Descriptors help article for more information.
Regards,
Yordanka
Telerik
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Padman
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answered on 20 Nov 2013, 01:49 PM
Hello
I have already seen this article but i required the exact access value for FieldFilter.FieldName in SL5. 2013.3.1016.1050
please provide your feedback.
I have already seen this article but i required the exact access value for FieldFilter.FieldName in SL5. 2013.3.1016.1050
please provide your feedback.
0
Hi,
Instead of FieldName now you have to use Filter1.Value or Filter2.Value:
Regards,
Yordanka
Telerik
Instead of FieldName now you have to use Filter1.Value or Filter2.Value:
columnDescriptor.FieldFilter.Filter1.Value = "Berlin";
Regards,
Yordanka
Telerik
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Padman
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answered on 21 Nov 2013, 05:29 AM
Hi
Yordanka,
I think your last answer was a result of misunderstood between us , Actually I required only FieldName. I mean FieldName as
on which Field, filter is applied.
Please let me know your feedback as soon as possible,
Thanks,
Padman
I think your last answer was a result of misunderstood between us , Actually I required only FieldName. I mean FieldName as
on which Field, filter is applied.
Please let me know your feedback as soon as possible,
Thanks,
Padman
0
Hi Padman,
After the changes introducing the new filtering mechanism, you don't need the Member and FieldName properties as you get the descriptor directly from the respective column. They are paired together so the Member is known.
Still, if you insist on this, you can take the Member of the column using its GetDataMemberName() method.
Regards,
Didie
Telerik
After the changes introducing the new filtering mechanism, you don't need the Member and FieldName properties as you get the descriptor directly from the respective column. They are paired together so the Member is known.
Still, if you insist on this, you can take the Member of the column using its GetDataMemberName() method.
Regards,
Didie
Telerik
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Padman
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answered on 25 Nov 2013, 06:02 AM
Hi Didie & Yordanka,
Thanks for great support however I have solved this issue by another way.
Regards,
Padman