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GridViewDataColumn.DataMemberBinding with multiple sources

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Christophe
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Christophe asked on 02 May 2011, 12:36 PM
Hello,

I need to create a GridView with a view model for each column (each column's view model is sharing with an another object).

This is my code behind:
...
for (int i = 0; i < max; i++)
{
    Binding MonBinding = new Binding("Points");
    MonBinding.Source = MonViewModel.CourbeTypeViewModels[i];
    MonBinding.Mode = BindingMode.OneWay;
 
    GridViewDataColumn GVDC = new GridViewDataColumn();
    GVDC.DataMemberBinding = MonBinding;
    GVDC.UniqueName = "ValCT" + i.ToString();
    GVDC.IsGroupable = false;
    GVDC.IsFilterable = false;
    GVDC.IsSortable = false;
    GVDC.IsReadOnly = true;
    Tableau.Columns.Add(GVDC);
}
...

My XAML :
...
<
telerik:RadGridView Name="Tableau" AutoGenerateColumns="False" IsFilteringAllowed="False" ShowGroupPanel="False">
                <telerik:RadGridView.Columns/>
</telerik:RadGridView>
...

In child view model :
...
private ObservableCollection<decimal> _Points;
public ObservableCollection<decimal> Points
{
    get { return _Points; }
    set
    {
        _Points = value;
        OnPropertyChanged("Points");
    }
}
...

MonViewModel is my page view model (datacontext)
CourbeTypeViewModels is an ObservableCollection of CourbeTypeViewModel view model in MonViewModel
Points is an ObservableCollection<decimal> in each CourbeTypeViewModel
Tableau is a GridView in my page

This code creating 3 columns with header but without data...

My question : "How can I bind each column with it's own viewmodel ?"   

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Vanya Pavlova
Telerik team
answered on 02 May 2011, 12:48 PM
Hi Christophe,

 

GridViewDataColumn is not designed to work in such scenarios. Why not use our ComboBoxColumn instead? 


Best wishes,
Vanya Pavlova
the Telerik team
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GridView
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Christophe
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Answers by
Vanya Pavlova
Telerik team
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