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error occurs when Editing cell

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GridView
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Kiran Ghanwat
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Kiran Ghanwat asked on 05 May 2010, 08:30 AM
Hello,

    currently, I am using version 2010.1.422.1030 for RadGridView, I gets the following error when I goes to edit the particular cell.
    (same thing happens to Version 2010.1.309.1030 too).
    Please, check attachment for error.

    Before, I was using version 2009.3.1103.1030 , that time it was working alright.

    Please, help.
    Thanks in advance.
    
Thanks,
Kiran Ghanwat.

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Milan
Telerik team
answered on 05 May 2010, 08:45 AM
Hi Kiran Ghanwat,

It seems that this there is some kind of problem with the references of your project. Could you please make sure that all Telerik assembly references have the same version number? Sometimes the references get mixed up you end up with one reference to the 422 version while all others are 309, for example. 


Kind regards,
Milan
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Kiran Ghanwat
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answered on 05 May 2010, 10:27 AM
Hey Milan,

    Thanks for your valueable reply.
    I checked version of all the dll's. those are same.
    I am getting this error when I tries to edit any cell in RadGridView.
    It seems that when I uses "RadControls_for_Silverlight_3_2010_1_0422_DEV_hotfix" binaries, that error occurs.

Regards,
Kiran Ghanwat.
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Veselin Vasilev
Telerik team
answered on 10 May 2010, 08:00 AM
Hello Kiran Ghanwat,

Please find attached a sample project. It uses the latest official release and is working as expected. Note that I am referencing the assemblies from the Binaries3 folder.

Best wishes,
Veskoni
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Kiran Ghanwat
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answered on 12 May 2010, 08:25 AM
Hello Milan,
    Thanks for your reply.    
    I have checked your sample. but, in that when I goes to edit any cell at first time ...the row containing that cell goes invisible.

    Thanks,
Kiran Ghanwat.

    
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Veselin Vasilev
Telerik team
answered on 17 May 2010, 08:27 AM
Hi Kiran Ghanwat,

You are right. Please add the ToList() at the end of the lambda expression:

gv1.ItemsSource = Enumerable.Range(0, 20).Select(i => new Item{ Name = "Item " + i.ToString(), ID = i }).ToList();

I hope this helps.

Regards,
Veskoni
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Kiran Ghanwat
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Answers by
Milan
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Kiran Ghanwat
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Veselin Vasilev
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