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I'm trying to add CustomLine to my chart with these lines of code:
...
The result is strange (look at the attached picture, the end of the line is [5,5]). Because there is little help and no examples at all, would somebody help me with this "tough" example?
I've tried everything in my mind (playing with Slope, YAxisName, ElementX1, etc.). Whatever I do I couldn't add a line that is rendered as I expect giving its properties
CustomLine line =
new
CustomLine();
line.StartX = 2;
line.StartY = 2;
line.EndX = 5;
line.EndY = 30; // !?!?
The result is strange (look at the attached picture, the end of the line is [5,5]). Because there is little help and no examples at all, would somebody help me with this "tough" example?
I've tried everything in my mind (playing with Slope, YAxisName, ElementX1, etc.). Whatever I do I couldn't add a line that is rendered as I expect giving its properties
6 Answers, 1 is accepted
0
Hello Georgi,
The StartX, EndX, etc properties do not represent coordinate points, they merely show where the line is clipped.The function which draws the custom line is : y = mx + b, where 'm' is the Slope and 'b' is YIntercept. The Slope is defined as : (y2 - y1)/(x2 - x1).
In your case, in order to draw a line from Point (2, 2) to Point(5, 30), you would need to define it in the following way:
Hope this helps. A help topic on the matter will be added in the nearest future.
Best wishes,
Nikolay
the Telerik team
The StartX, EndX, etc properties do not represent coordinate points, they merely show where the line is clipped.The function which draws the custom line is : y = mx + b, where 'm' is the Slope and 'b' is YIntercept. The Slope is defined as : (y2 - y1)/(x2 - x1).
In your case, in order to draw a line from Point (2, 2) to Point(5, 30), you would need to define it in the following way:
RadChart1.DefaultView.ChartArea.Annotations.Add(new CustomLine() { StartX = 2, EndX = 5, YIntercept = -16.66, Slope = 9.33});
Hope this helps. A help topic on the matter will be added in the nearest future.
Best wishes,
Nikolay
the Telerik team
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0
Georgi
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Rank 1
answered on 16 Sep 2010, 03:25 PM
Knowing the actual function that represents the line and some base trigonometry from high school it takes a few lines of code to draw almost every possible line with starting and ending coordinates as input. So thanks for the hint :)
But I said almost every possible line... what about a vertical line? My basic math knowledge tells me that it's not possible with your approach, is it? :) And is there any other way to draw a line from (2, 2) to (2,4)?
I'm not such a stickler, I just try to find some solution for my other problems with MarkedZones (look here). If I can find a way to draw vertical lines, then I can just draw 4 lines to form a rectangle, don't I?
But I said almost every possible line... what about a vertical line? My basic math knowledge tells me that it's not possible with your approach, is it? :) And is there any other way to draw a line from (2, 2) to (2,4)?
I'm not such a stickler, I just try to find some solution for my other problems with MarkedZones (look here). If I can find a way to draw vertical lines, then I can just draw 4 lines to form a rectangle, don't I?
0
Hello Georgi,
You can draw a vertical line from Point( 2, 2 ) to Point( 2, 4 ) by setting PositiveInfinity for the Slope. Here is a sample code snippet :
Hope this helps.
Sincerely yours,
Nikolay
the Telerik team
You can draw a vertical line from Point( 2, 2 ) to Point( 2, 4 ) by setting PositiveInfinity for the Slope. Here is a sample code snippet :
RadChart1.DefaultView.ChartArea.Annotations.Add(new CustomLine() { StartY = 2, EndY = 4, XIntercept = 2, Slope = double.PositiveInfinity });
Hope this helps.
Sincerely yours,
Nikolay
the Telerik team
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0
Brian
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Rank 1
answered on 04 Aug 2011, 03:19 PM
I am trying to create a horizontal custom line. Using your instructions above, that would be:
new CustomLine { YIntercept = 5, Slope = double.PositiveInfinity, MinX = 5, MaxX = 15 };
for a line with a Y value of 5 that extends from X=5 to X=15, right? It doesn't seem to work. I can't get it to actually draw the line.
new CustomLine { YIntercept = 5, Slope = double.PositiveInfinity, MinX = 5, MaxX = 15 };
for a line with a Y value of 5 that extends from X=5 to X=15, right? It doesn't seem to work. I can't get it to actually draw the line.
0
Hello Brian,
Please find our answer in the other forum thread concerning the same issue.
Greetings,
Sia
the Telerik team
Please find our answer in the other forum thread concerning the same issue.
Greetings,
Sia
the Telerik team
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0
Manesh
Top achievements
Rank 2
answered on 01 Feb 2012, 11:20 AM
HELLO GEORGI,
This is manesh its nice to see custom line working in your programming but i'm unable to have custome line syntax error is comming so please tell me how to write it or please mail your code to manesh561@gmail.com
This is manesh its nice to see custom line working in your programming but i'm unable to have custome line syntax error is comming so please tell me how to write it or please mail your code to manesh561@gmail.com