Drag & Drop Image from RadGridView

[Anthony Korkmaz]

Hello,

Q1 2010 VS2008 SL3
I have a GridView that contains an image in the first column, when I drag the row I don't want it to display the PrimaryKey of the row I'm dragging but I want it to show the image that is displayed in the first column.
The problem is that the image is stored in Bytes[] in the database so I cant give the field as a Source to the image control and put it in the DragCue...
I tried something like this in OnContactDragInfo :

            if (e.Options.Status == DragStatus.DragInProgress)
            {            
                ContentControl cue = new ContentControl();
                cue.ContentTemplate = ((Party)(gvContacts.SelectedItem)).Photo as DataTemplate;
                cue.Content = gvContacts.SelectedItem;
                e.Options.DragCue = cue;
            }

But VS is giving this error "Cannot convert type 'byte[]' to 'System.Windows.DataTemplate' " on ((Party)(gvContacts.SelectedItem)).Photo as DataTemplate
NB: The image is displaying fine in the grid view... so can I just take the first item from the GridView whatever it is and give it to the DragCue?

Thanks for your help,

Anthony

[Kiril Stanoev]

Hi Anthony,

I assume the Photo property of the Party business object is the one containing the byte array. If that is the case, you will have to convert the byte array to a BitmapImage. Then create an Image control and set its Source to be the BitmapImage. Finally you can pass the Image as a Content to the cue:

if (e.Options.Status == DragStatus.DragInProgress)
{
    ContentControl cue = new ContentControl();
    byte[] bytes = ((Party)(gvContacts.SelectedItem)).Photo;
    BitmapImage bmpImage = ImageFromBuffer(bytes);
    Image image = new Image();
    image.Source = bmpImage;
    cue.Content = image;
    e.Options.DragCue = cue;
}



// Method to convert byte array to BitmapImage
public BitmapImage ImageFromBuffer(Byte[] bytes)
{
    MemoryStream stream = new MemoryStream(bytes);
    BitmapImage image = new BitmapImage();
    image.BeginInit();
    image.StreamSource = stream;
    image.EndInit();
    return image;
}

Give it a try and let me know how it goes.

Kind regards,
Kiril Stanoev
the Telerik team

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