How to tell Find.ByType not to throw an exception

[Kristine]

Hello Telerik Team,

I need to find an element by using the Find.ByType method. If the element is not found, I want my test to proceed without the Find method throwing an exception. Please see this code:

foreach(Telerik.WebAii.Controls.Xaml.GridViewRow row in Rows)
{
        Telerik.WebAii.Controls.Xaml.RadGridView childgrid = row.Find.ByType<Telerik.WebAii.Controls.Xaml.RadGridView>();
}

I want my test to proceed even if childgrid is null. However, the test is stopping because row.Find.ByType is throwing a timeout exception. Any suggestions?

Regards,
Kristine

[Stoich]

Hello Kristine,
    generally if you catch the exception like this:

foreach(Telerik.WebAii.Controls.Xaml.GridViewRow row in Rows) {
try{
        Telerik.WebAii.Controls.Xaml.RadGridView childgrid = row.Find.ByType<Telerik.WebAii.Controls.Xaml.RadGridView>();
}
catch (Exception e) { }
}

then your test won't stop executing. However, could you please paste the Timeout error from the log. I'm curious to see what's throwing it because I believe row.Find.ByType<Telerik.WebAii.Controls.Xaml.RadGridView>(); is supposed to simply return NULL if it can't find anything.

Best wishes,
Stoich
the Telerik team

[Cody]

Hello Kristine,

Another, probably easier approach, is to change the find strategy right before calling Find like this:

foreach (Telerik.WebAii.Controls.Xaml.GridViewRow row in Rows)
{
    row.Find.Strategy = FindStrategy.WhenNotVisibleReturnNull;
    Telerik.WebAii.Controls.Xaml.RadGridView childgrid = row.Find.ByType<Telerik.WebAii.Controls.Xaml.RadGridView>();
}

Regards,
Cody
the Telerik team

[Kristine]

Hi Stoich and Cody,

I was able to resolve the problem using Stoich's solution. I'll try Cody's next time. Thanks so much!

Regards,
Kristine