Home / Community & Support / Developer Productivity Tools Forums / ASP.NET AJAX > Ajax > Easy ?: Server Needs Label Changed Client Side

• James

  Posted on Feb 6, 2012 (permalink)

  I think this is an easy question, and I'm a little perplexed that I am having a problem with it.  Here is the issue:
  
  This code grabs the DataKeyValue from a RadGrid row onRowMouseOver with no problem:
  
  

  function onRowMouseOver(sender, eventArgs) {

      var rowID = eventArgs.getDataKeyValue("PartyExperienceID");

      document.getElementById("<%= HiddenLabel.ClientID %>").innerHTML = rowID;

  }  

  
  Works like a dream.  Now, I want to grab the changed HiddenLabel value server side (any way is fine, even a button click).  I can see that the label has changed on the page, but the server cannot see the change.  I'm wondering if I can solve the problem via RadAjaxManager.  Here is my current config:
  
  

  <telerik:RadAjaxManager runat="server" ID="RadAjaxManager1">

      <AjaxSettings>

          <telerik:AjaxSetting AjaxControlID="RadAjaxManager1">

              <UpdatedControls>

                  <telerik:AjaxUpdatedControl ControlID="HiddenLabel" />

              </UpdatedControls>

          </telerik:AjaxSetting>

          <telerik:AjaxSetting AjaxControlID="RadTreeView1">

              <UpdatedControls>

                  <telerik:AjaxUpdatedControl ControlID="RadTreeView1" />

                  <telerik:AjaxUpdatedControl ControlID="RadGrid1" />

              </UpdatedControls>

          </telerik:AjaxSetting>

          <telerik:AjaxSetting AjaxControlID="RadGrid1">

              <UpdatedControls>

                  <telerik:AjaxUpdatedControl ControlID="HiddenLabel" />

              </UpdatedControls>

          </telerik:AjaxSetting>

      </AjaxSettings>

  </telerik:RadAjaxManager>

  
  Any other ideas?   I feel I am missing something obvious (not a JS guy).
  
  Thanks so much!
  
  Jim

  Reply

• James

  Posted on Feb 6, 2012 (permalink)

  Sorry, been a long day programming.  I will just use a hidden field instead of a label.
  
  Thanks,
  
  Jim

  Reply

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