ClientGroupFooterTemplate question

3 posts, 0 answers
  1. Alan Mosley
    Alan Mosley avatar
    200 posts
    Member since:
    Apr 2010

    Posted 10 Aug 2015 Link to this post

    I want to divide one aggregate by another.

    Take these aggregates

                               aggregates.Add(Function(p) p.Total).Min().Max.Count()
                               aggregates.Add(Function(p) p.Total).Average()
                               aggregates.Add(Function(p) p.Total).Sum()
                               aggregates.Add(Function(p) p.Enrolments).Average()
                               aggregates.Add(Function(p) p.Enrolments).Sum()
                               aggregates.Add(Function(p) p.StudentEvents).Average()
                               aggregates.Add(Function(p) p.StudentEvents).Sum()
                               aggregates.Add(Function(p) p.Products).Average()
                               aggregates.Add(Function(p) p.Products).Sum()
                               aggregates.Add(Function(p) p.Male).Sum()
                               aggregates.Add(Function(p) p.Female).Sum()
                               aggregates.Add(Function(p) p.Students).Sum()
                       End Sub).

    I want to do something like this below, note "sum / Students " where sum is the sum of enrolments and students is the sum of students, is this possible? thanks


    columns.Bound(Function(p) p.Enrolments).Format("{0:C}").
                            ClientFooterTemplate("Avg #= kendo.toString(sum / Students ,'C')#<br />Total #= kendo.toString(sum ,'C')#").
                            ClientGroupFooterTemplate("<div>Avg #= kendo.toString(sum / Students ,'C')#</div><div>Total #= kendo.toString(sum ,'C')#</div>")


  2. Rosen
    Rosen avatar
    3214 posts

    Posted 12 Aug 2015 Link to this post

    Hello Alan,

    Indeed, you can access the values of other column aggregates inside the ClientFooterTemplate/GroupFooterTemplate. It can be done via similar to the following syntax:

    ClientFooterTemplate("Avg #= kendo.toString(data.Enrolments.sum/ data.Students.count,'C')#<br />Total #= kendo.toString(sum ,'C')#")

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  4. Alan Mosley
    Alan Mosley avatar
    200 posts
    Member since:
    Apr 2010

    Posted 12 Aug 2015 in reply to Rosen Link to this post

    Thanks Rosen
    Good to see.
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